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given
\(m < x < n\) and \(p < y < r\),
target is to check whether \(\frac{x}{y} < 0\)

#1
\(−|n− m| = |n| − |m| < 0\)
with given condition
\(m < x < n\)

only possibility is m & n being both -ve ; eg m= -5 and n =-3
-l-3+5l=l-3l-l-5l
-2=-2
but no info about y so insufficient

#2
\(|p− r| = |p| − |r| > 0\)

given condition
\(p < y < r\)
r=-3 and p=-5
l-5+3l=l-5l-l-3l
2=2
but no info about x
insufficient
from 1 &2
we can say that value of x & y would fall in range of -ve values so \(\frac{x}{y} < 0\) is NO
hence option C is sufficient

Bunuel
If \(m < x < n\) and \(p < y < r\), is \(\frac{x}{y} < 0\)?


(1) \(−|n− m| = |n| − |m| < 0\)

(2) \(|p− r| = |p| − |r| > 0\)



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Bunuel
If \(m < x < n\) and \(p < y < r\), is \(\frac{x}{y} < 0\)?
(1) \(−|n− m| = |n| − |m| < 0\)
(2) \(|p− r| = |p| − |r| > 0\)

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m < x < n and p < y < r
Thus, we need information about m, n and also about p, r. Thus, we definitely need to combine the statements.

From 1: -|n - m| = |n| - |m| < 0
=> |n - m| = |m| - |n| > 0
=> |m| > |n|
Also: |n - m| = |m - n| = |m| - |n| => m and n are both of the same sign (both positive or both negative)
However, we already have: m < n
Thus, m is a negative number and hence, n is negative but smaller magnitude than m
For example: m = -6, n = -2
=> x is negative (since y lies between m and n)

From 2: |p− r| = |p| − |r| > 0
=> |p| > |r|
Also: |p - r| = |p| - |r| => p and r are both of the same sign (both positive or both negative)
However, we already have: p < r
Thus, p is a negative number and hence, r is negative but smaller magnitude than m
For example: p = -6, r = -2
=> y is negative (since y lies between p and r)

Thus: x/y > 0

Answer C
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m<x<n
p<y<r
Is x/y<0?
Statement 1: - mod (n-m)= mod (n)- mod(m)<0
x#0 and x<0
No info about y
Insufficient
Statement 2: mod (p-r)= mod (p)-mod(r)>0
y#0 and y>0
Insufficient
Both statements together
x<0 and y>0
Sufficient
C
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sujoykrdatta

Also: |n - m| = |m - n| = |m| - |n| => m and n are both of the same sign (both positive or both negative).

I really struggle in these questions of mod; please explain me this?
And also, how important is mod for gmat?
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Best way to understand is to take some numbers:
First of all, |m-n| = |n-m| since even if we multiply the inside of a mod by a '-1', there is no change - after all, mod removes the effect of the negative.

Now, we need to check:

|m - n| = |m| - |n| .... (A)

Say m=4,n=1: both sides of (A) above equal 3

Say m=-4,n=-1: both sides of (A) above equal 3

Say m=4,n=-1: left side equals 5 while the right side equals 3 => not equal

Thus, only when m and n were both positive or both negative, i.e. m and n are of same sign, (A) holds true



Mod => pretty important :)

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DaniyalAlwani
sujoykrdatta

Also: |n - m| = |m - n| = |m| - |n| => m and n are both of the same sign (both positive or both negative).

I really struggle in these questions of mod; please explain me this?
And also, how important is mod for gmat?


Forgot to tag you - please check my response above

Posted from my mobile device
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nick1816

Can you please tell why you have not selected values of m and n , i.e. m = - 0.75 and n = 0.25 In this case ImI > InI. The original eqn. m < n still holds valid. Thus x can be +ve or -ve and not just -ve.

Same goes for Condition 2, i.e. y can be +ve or -ve since IpI > IrI where r can be either +ve or -ve, and p is always -ve.

Will appreciate any help?
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rye
(1) −|n−m|=|n|−|m|<0

or |n−m|=|m|−|n|

Now put the values you consider for m and n

|n−m|=|0.25-(-0.75)|=1

|m|−|n|= |-0.75|-|0.25| = 0.5

So the values you consider doesn't satisfy the statement 1. Same goes with other case. If you still have any doubt, you can ask.
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