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Re: If n and m are positive integers, is n/m equal to a [#permalink]
I guess the "/" is just a delimiter to specify the statement number :) It is not 1/n or 2/m.
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Re: If n and m are positive integers, is n/m equal to a [#permalink]
ohh ok...that made a good DS too though :-D
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Re: If n and m are positive integers, is n/m equal to a [#permalink]
abhivarma03 wrote:
IMO its E.

n=1/60,1/120 ....

lets break these into prime factors.
60=2*2*3*5

m=1/125,1/250 ....
125=5*5*5

n/m=125/60..now number doesnt have a 3,so let me how it terminate.

My Pick E.

Please get the OA...

Yup you are right :)
But then the answer would be B.
Because, even if we consider 1/n...n can ONLY be 1..because a fraction cannot be a factor of an integer. But this is not sufficient.

Similarly m can ONLY be 1. That is sufficient.:wink:
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Re: If n and m are positive integers, is n/m equal to a [#permalink]
Economist wrote:
I guess the "/" is just a delimiter to specify the statement number :) It is not 1/n or 2/m.



Sorry dudes for this confusion.
The answer is C.

Thanks
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Re: If n and m are positive integers, is n/m equal to a [#permalink]
I have a small doubt...

As m can only have factors 1,2 and 5.. should stmt B in itself not be sufficient to answer the question?

P.S. I am assuming here that any fraction divided by 2 or 5 will lead to a terminating decimal..
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Re: If n and m are positive integers, is n/m equal to a [#permalink]
rvthryet wrote:
I have a small doubt...

As m can only have factors 1,2 and 5.. should stmt B in itself not be sufficient to answer the question?

P.S. I am assuming here that any fraction divided by 2 or 5 will lead to a terminating decimal..


I agree. Answer should be B and not C.
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Re: If n and m are positive integers, is n/m equal to a [#permalink]
IMO answer should be B....

1. n is a factor of 60. no information about B... insuff
2. m is a factor of 250....prime factors of 250 are 5 and 2...divide any number by 5 & 2 will result into terminating decimal
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Re: If n and m are positive integers, is n/m equal to a [#permalink]
Correct guys :) I meant B and not C.
andrewg can you please re-check OA?



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