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# If N is a multiple of 3, is the N/3 an odd integer?

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If N is a multiple of 3, is the N/3 an odd integer?  [#permalink]

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22 Oct 2017, 06:39
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If N is a multiple of 3, is the N/3 an odd integer?

(1) N = 3K where K is an integer.
(2) N = 6J + 3 where J is an integer

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Re: If N is a multiple of 3, is the N/3 an odd integer?  [#permalink]

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22 Oct 2017, 10:46
Bunuel wrote:
If N is a multiple of 3, is the N/3 an odd integer?

(1) N = 3K where K is an integer.
(2) N = 6J + 3 where J is an integer

S1 - N=3K
N/3 can be even or odd.
Insufficient.

S2 - N = 6J + 3
N/3 = 2J+1
2J is always even and even no. + 1 =odd no.
Sufficient.

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Re: If N is a multiple of 3, is the N/3 an odd integer?  [#permalink]

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22 Oct 2017, 10:51
(1) N = 3K so N/3 = 3K/3 = k. Now whether this is even or odd depends on the value of k, which we don't know. So Insufficient.

(2) N = 6J + 3, so N/3 = 6J/3 + 3/3 = 2J + 1. This will definitely be odd since J is an integer and 2J is even (so 2J+1 will be odd). Sufficient.

Re: If N is a multiple of 3, is the N/3 an odd integer? &nbs [#permalink] 22 Oct 2017, 10:51
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# If N is a multiple of 3, is the N/3 an odd integer?

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