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n - a positive integer

\((\frac{1}{n})-(\frac{1}{n+1})\)< 0.05

\(\frac{(n+1-n)}{n(n+1)}\)< \(\frac{1}{20}\)

--> \(\frac{1}{n(n+1)}\)< \(\frac{1}{20}\)

\((\frac{1}{20})- \frac{1}{n(n+1)}\)> 0

\(\frac{n(n+1)- 20}{n(n+1)*20}\) >0

\(\frac{n^{2}+n-20}{n(n+1)*20}\) >0

\(\frac{(n+5)(n-4)}{n(n+1)*20}\) >0

--> n< -5, -1<n<0, n>4

n is a positive integer --> n>4 ???

(Statement1): n is odd.
Clearly insufficient

(Statement2): n is a positive multiple of 7
n =7,14,21,....

Sufficient.

The answer is B.
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S1 - n is odd,
take n = 1, we get 0.5 which is equal to RHS(0.5)
take n =3, we get 1/12 which is less than RHS(0.5)
conflicting results - Insufficient Statement

S2 - n is positive multiple of 7 (7,14,21.....)
take n = 7, we get 1/56 which is less than RHS(0.5)
take n = 14, results less than RHS(0.5)... and so on for higher values. - Sufficient Statement

Answer is Option B
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My question is if 0 is multiple of every number, then n could be 0 too.. please explain where i am wrong.

although I choose B. But this question popped up in my mind.

Posted from my mobile device
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Mansi89
My question is if 0 is multiple of every number, then n could be 0 too.. please explain where i am wrong.

although I choose B. But this question popped up in my mind.

Posted from my mobile device

The question says “ if n is positive integer....” —> n > 0(zero). Well, your explanation does not match this solution.
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