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If n is a positive integer, is n – 1 divisible by 3?
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19 Jun 2015, 02:12
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Re: If n is a positive integer, is n – 1 divisible by 3?
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19 Jun 2015, 03:22
If n is a positive integer, is n – 1 divisible by 3?
(1) n^2 + n is not divisible by 6.
n^2+n = n(n+1)
Lets assume n1 divisible by 3, n = 4,7,10,13,16 .......
For all the values of n, n(n+1) is not divisible by 6. So our assumption n1 is divisible by 3 is true Sufficient.
(2) 3n = k + 3, where k is a positive multiple of 3.
Since K is a positive multiple of 3, the above equation can be rewritten as 3n = 3K+3, where k =1,2,3,4,5,6,7....... 3n= 3(K+1) n=K+1 n1 = k
So Clearly n1 is divisible by 3.
Sufficient
Ans:D
Manoj Reddy Please press +1 Kudos if the post helped you!!!



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Re: If n is a positive integer, is n – 1 divisible by 3?
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19 Jun 2015, 03:27
I Think answer is A. Option 1 N^2+ N not divisible by 6 => N can be 1, 4, 7 and 10. From the above N1= 0, 3, 6, 9 (All are divisible by 3) Sufficient. Option 2 3N= K+3 => K can be 3, 6, 9 and 12 etc. Then N can be equal to 2, 3, 4, 5 Respectively. Of the above numbers, N1 => 1 and 2 are not divisible by 3 but 41 is divisible by 3. Hence not sufficient. Option A. Bunuel wrote: If n is a positive integer, is n – 1 divisible by 3?
(1) n^2 + n is not divisible by 6. (2) 3n = k + 3, where k is a positive multiple of 3.
Kudos for a correct solution.
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Re: If n is a positive integer, is n – 1 divisible by 3?
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19 Jun 2015, 09:31
@ManojReddy wrote: If n is a positive integer, is n – 1 divisible by 3?
(1) n^2 + n is not divisible by 6.
n^2+n = n(n+1)
Lets assume n1 divisible by 3, n = 4,7,10,13,16 .......
For all the values of n, n(n+1) is not divisible by 6. So our assumption n1 is divisible by 3 is true Sufficient.
(2) 3n = k + 3, where k is a positive multiple of 3.
Since K is a positive multiple of 3, the above equation can be rewritten as 3n = 3K+3, where k =1,2,3,4,5,6,7....... 3n= 3(K+1) n=K+1 n1 = k
So Clearly n1 is divisible by 3.
Sufficient
Ans:D
Manoj Reddy Please press +1 Kudos if the post helped you!!! Hi, you have gone wrong by cancelling out 3 from both sides.. 3n = k + 3 3n3=k 3(n1)=k... we are given k is a multiple of 3, which can be seen from the result but n1 can take any value.. hope it is clear
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Re: If n is a positive integer, is n – 1 divisible by 3?
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19 Jun 2015, 09:34
Bunuel wrote: If n is a positive integer, is n – 1 divisible by 3?
(1) n^2 + n is not divisible by 6. (2) 3n = k + 3, where k is a positive multiple of 3.
Kudos for a correct solution. 1)n^2 + n =n(n+1) is not div by 3.. but as the two numbers are consecutive one of them has to be even and it is not div by 3... if n and n+1 are not div by 3.. n1 must be div by3.. suff 2)3n = k + 3 3n3=k 3(n1)=k... we are given k is a multiple of 3, which can be seen from the result but n1 can take any value.. insuff ans A
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Re: If n is a positive integer, is n – 1 divisible by 3?
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22 Jun 2015, 06:15
Bunuel wrote: If n is a positive integer, is n – 1 divisible by 3?
(1) n^2 + n is not divisible by 6. (2) 3n = k + 3, where k is a positive multiple of 3.
Kudos for a correct solution. MANHATTAN GMAT OFFICIAL SOLUTION:An accurate yes/no rephrase is the following: Is (n  1)/2 = integer? Is n – 1 = 3 × integer? Is n = 3 × integer + 1? Is the positive integer n one greater than a multiple of 3? This narrows down our values of interest to a certain type of number, which follows a pattern: 1, 4, 7, 10, etc. A value question such as “What is n?” would be unnecessarily picky. We don't need to know the exact value, just whether n is a certain type of number. (1) SUFFICIENT: If n^2 + n = n(n + 1) is not divisible by 6, we can rule out certain values for n. The correct yes/no rephrasing directs us to look for a certain pattern. We see that pattern here: n can only be 1, 4, 7, 10, etc., all integers that are one greater than a multiple of 3. (2) INSUFFICIENT: If 3n = 3 × pos integer + 3, then n = pos integer + 1. Therefore, n is an integer such that n ≥ 2. This does not resolve whether n is definitely one greater than a multiple of 3. The correct answer is A.Attachment:
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If n is a positive integer, is n – 1 divisible by 3?
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11 Feb 2016, 19:35
Bunuel wrote: If n is a positive integer, is n – 1 divisible by 3?
(1) n^2 + n is not divisible by 6. (2) 3n = k + 3, where k is a positive multiple of 3.
Kudos for a correct solution. I answered A, but now don't seem so confident... 1. n(n+1) not divisible by 6. or not divisible by 2 nor 3. we have consecutive numbers. we can have 1x2, 2x3, 3x4, 4x5, or we can have 7x8, 10x11.. where n=7 or 10. 71=6 and is divisible by 3. 101=9, and is divisible by 3. 2. 3n=k+3, where k is multiple of 3. if k=3, then n=2 > n1 not divisible by 3. if k=9, then n=4 > n1 divisible by 3. 2 different answers, so can't be B. p.s. thanks to the above comments.. I indeed remembered that x(x+1)(x1) is always divisible by 3. if x(x+1) is not divisible by 3, then x1 MUST be divisible by 3.



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Re: If n is a positive integer, is n – 1 divisible by 3?
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13 Feb 2016, 23:04
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution. If n is a positive integer, is n – 1 divisible by 3? (1) n^2 + n is not divisible by 6. (2) 3n = k + 3, where k is a positive multiple of 3. In the original condition, there is 1 variable(n), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer. For 1), since n(n+1) is not multiple of 6, it becomes an integer of n=3m+1 like n=1,4,7,10..... Thus, it becomes n1=3m, which is yes and sufficient. For 2), 3n=3m+3 > n=m+1 > n1=m. Thus, m=2 > no and m=3 > yes, which is not sufficient. Therefore, the answer is A. For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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