janosfazekas91 wrote:

If n is a prime number, which of the following could be true?

A. n^n=n

B. n^2/4= is even

C. (n)(n^n) = is negative

D. n^2+n^3= n^5

E. n^n/4 = 1^(n-1)

A. n^n = n

n(n^(n-1) - 1)

So, n =1 is only possible value.

B. if we put value, 2 then 2^2/4 = 1 is odd. In other cases n^2/4 has decimal value.

C. n(n^n) can never be -ve for prime numbers

D. n^2 + n^3 = n^5

n^2 (n^3-n+1) = 0

No such prime number exists

E. For n =2 , n^n/4 = 1^(n-1) is true.

So,

Answer E
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