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Math Expert V
Joined: 02 Sep 2009
Posts: 58335
If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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Difficulty:   45% (medium)

Question Stats: 49% (01:09) correct 51% (01:28) wrong based on 45 sessions

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If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten

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Intern  B
Joined: 28 Sep 2018
Posts: 29
If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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Given:-
99 < N^2 < 200
N is an integer

Inference:-
N is a perfect square

Solution:-
We need to find all the perfect squares that lie between 99 and 200 exclusive

10^2= 100
11^2= 121
13^2= 169
14^2= 196

Thus there are four values of N that satisfies the given constraint

(B)
VP  D
Joined: 31 Oct 2013
Posts: 1475
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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Hoozan wrote:
Given:-
99 < N^2 < 200
N is an integer

Inference:-
N is a perfect square

Solution:-
We need to find all the perfect squares that lie between 99 and 200 exclusive

10^2= 100
11^2= 121
13^2= 169
14^2= 196

Thus there are four values of N that satisfies the given constraint

(B)

where is 12. 12^2 = 144. a value belongs to this range.

**** u are dealing with perfect square thus u have to consider negative values too.

(-10)^2 =100
(10)^2 = 100

thus , for each positive value there will be a same negative value.
VP  D
Joined: 31 Oct 2013
Posts: 1475
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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Bunuel wrote:
If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten

Minimum value of N = 10

Max value of N = 14.

N = 10, 11 , 12 , 13 , 14.

As we are dealing with perfect square , we must consider negative values too.

N = -10 , -11, -12, -13, -14.

There will be 10 values in total.

E is the correct answer.

Originally posted by KSBGC on 06 Feb 2019, 04:05.
Last edited by KSBGC on 06 Feb 2019, 04:17, edited 1 time in total.
Intern  B
Joined: 28 Sep 2018
Posts: 29
Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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Thanks for bringing it to my notice

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Director  G
Joined: 09 Mar 2018
Posts: 997
Location: India
Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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Bunuel wrote:
If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten

so lets see, easiest approach will be just write the numbers between the range 99 < N^2 < 200

10,11,12,13,14

Five +ive, Five -ive integers since it is a square you can take both values.

Total 10
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GMAT Club Legend  D
Joined: 18 Aug 2017
Posts: 4976
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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Bunuel wrote:
If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten

N= 10,11,12,13,14
and - ve values of N would lie in range 99 < N^2 < 200
IMO E 10
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If you liked my solution then please give Kudos. Kudos encourage active discussions. Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m   [#permalink] 06 Feb 2019, 05:32
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