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If N is an integer and 99 < N^2 < 200, then N could have at most how m

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If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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New post 06 Feb 2019, 02:40
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

43% (01:16) correct 57% (01:29) wrong based on 21 sessions

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If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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New post 06 Feb 2019, 02:47
Given:-
99 < N^2 < 200
N is an integer

Inference:-
N is a perfect square

Solution:-
We need to find all the perfect squares that lie between 99 and 200 exclusive

10^2= 100
11^2= 121
13^2= 169
14^2= 196

Thus there are four values of N that satisfies the given constraint

(B)
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Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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New post 06 Feb 2019, 03:02
Hoozan wrote:
Given:-
99 < N^2 < 200
N is an integer

Inference:-
N is a perfect square

Solution:-
We need to find all the perfect squares that lie between 99 and 200 exclusive

10^2= 100
11^2= 121
13^2= 169
14^2= 196

Thus there are four values of N that satisfies the given constraint

(B)



where is 12. 12^2 = 144. a value belongs to this range.

**** u are dealing with perfect square thus u have to consider negative values too.

(-10)^2 =100
(10)^2 = 100

thus , for each positive value there will be a same negative value.
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If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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New post Updated on: 06 Feb 2019, 03:17
Bunuel wrote:
If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten



Minimum value of N = 10

Max value of N = 14.

N = 10, 11 , 12 , 13 , 14.

As we are dealing with perfect square , we must consider negative values too.

N = -10 , -11, -12, -13, -14.

There will be 10 values in total.

E is the correct answer.

Originally posted by selim on 06 Feb 2019, 03:05.
Last edited by selim on 06 Feb 2019, 03:17, edited 1 time in total.
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Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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New post 06 Feb 2019, 03:11
Thanks for bringing it to my notice

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Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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New post 06 Feb 2019, 03:17
Bunuel wrote:
If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten


so lets see, easiest approach will be just write the numbers between the range 99 < N^2 < 200

10,11,12,13,14

Five +ive, Five -ive integers since it is a square you can take both values.

Total 10
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Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m  [#permalink]

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New post 06 Feb 2019, 04:32
Bunuel wrote:
If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten


N= 10,11,12,13,14
and - ve values of N would lie in range 99 < N^2 < 200
IMO E 10
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Re: If N is an integer and 99 < N^2 < 200, then N could have at most how m   [#permalink] 06 Feb 2019, 04:32
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