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05 Jul 2016, 11:55
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
70% (00:43) correct
30%
(00:57)
wrong
based on 627
sessions
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If n is an integer, then the least possible value of |31 - 4n| is?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
GMAT Total Maths
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
GMAT Total Maths
05 Jul 2016, 12:07
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HarveyKlaus
|31 - 4n| represents the distance between 31 and 4n on the number line. Now, the distance will be minimized when 4n, which is multiple of 4, is closest to 31. Multiple of 4 which is closest to 31 is 32 (for n = 8), so the least distance is 1: |31 - 32| = 1.
Answer: B.
Hope it's clear.
General Discussion
hsbinfy
Joined: 02 Mar 2012
Last visit: 13 Nov 2017
Posts: 190
Own Kudos:
Given Kudos: 4
Schools: Schulich '16
05 Jul 2016, 22:54
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when modulus questions are there think about DISTANCE and modulus is always absolute value i.e positive
|31-4n|
so the minimum would be when n=8..the distance would be the least from 31 i.e.1
don't worry abut -ve or +ve value inside the modulus.coz mod is always +ve
so answer here is B
|31-4n|
so the minimum would be when n=8..the distance would be the least from 31 i.e.1
don't worry abut -ve or +ve value inside the modulus.coz mod is always +ve
so answer here is B
