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If n is an integer, then the least possible value of l31 - 4nl is

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If n is an integer, then the least possible value of l31 - 4nl is  [#permalink]

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New post 05 Jul 2016, 11:55
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Question Stats:

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If n is an integer, then the least possible value of |31 - 4n| is?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

GMAT Total Maths
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Re: If n is an integer, then the least possible value of l31 - 4nl is  [#permalink]

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New post 05 Jul 2016, 12:07
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HarveyKlaus wrote:
Hi All;

I found this question in GMAT Total Maths, but Im not able to understand the solution provided. Would appreciate if someone could please comment? Thanks

If n is an integer, then the least possible value of |31 - 4n| is?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4


|31 - 4n| represents the distance between 31 and 4n on the number line. Now, the distance will be minimized when 4n, which is multiple of 4, is closest to 31. Multiple of 4 which is closest to 31 is 32 (for n = 8), so the least distance is 1: |31 - 32| = 1.

Answer: B.

Hope it's clear.
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Re: If n is an integer, then the least possible value of l31 - 4nl is  [#permalink]

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New post 05 Jul 2016, 22:54
when modulus questions are there think about DISTANCE and modulus is always absolute value i.e positive

|31-4n|

so the minimum would be when n=8..the distance would be the least from 31 i.e.1

don't worry abut -ve or +ve value inside the modulus.coz mod is always +ve

so answer here is B
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Re: If n is an integer, then the least possible value of l31 - 4nl is  [#permalink]

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New post 09 Mar 2018, 09:25
HarveyKlaus wrote:
If n is an integer, then the least possible value of |31 - 4n| is?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

GMAT Total Maths


Please note that question is not asking the least value of "n".

32 is the closest integer to 31 which we can get by multiplying 4*8.

Therefore, |31 - 4*8| = 1

Hence, (B)
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Re: If n is an integer, then the least possible value of l31 - 4nl is &nbs [#permalink] 09 Mar 2018, 09:25
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