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# If ¡n! = (n!)^2, then ¡17! – ¡16! =

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Intern
Joined: 10 Mar 2015
Posts: 2
If ¡n! = (n!)^2, then ¡17! – ¡16! =  [#permalink]

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22 Jul 2018, 22:55
00:00

Difficulty:

(N/A)

Question Stats:

75% (02:24) correct 25% (02:54) wrong based on 4 sessions

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If ¡n! = (n!)^2, then ¡17! – ¡16! =
a. ¡1!
b. (¡16!)(¡4!)(2)
c. (¡16!)(12)(2)
d. 17^2
e. (¡16!)(12^2)(2)
Math Expert
Joined: 02 Sep 2009
Posts: 49430
Re: If ¡n! = (n!)^2, then ¡17! – ¡16! =  [#permalink]

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22 Jul 2018, 23:02
nivivacious wrote:
If ¡n! = (n!)^2, then ¡17! – ¡16! =
a. ¡1!
b. (¡16!)(¡4!)(2)
c. (¡16!)(12)(2)
d. 17^2
e. (¡16!)(12^2)(2)

This question is here: https://gmatclub.com/forum/if-n-n-2-then-162389.html Please continue discussion in that topic.
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Re: If ¡n! = (n!)^2, then ¡17! – ¡16! = &nbs [#permalink] 22 Jul 2018, 23:02
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# If ¡n! = (n!)^2, then ¡17! – ¡16! =

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