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Bunuel
If \(n + n = k+ k + k\) and \(n+k = 5\), the \(n =\)

A. 2

B. 3

C. 5

D. 6

E. 9

given
2n=3k
k=5-n
solve for n
n=3
IMO B
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Bunuel
If \(n + n = k+ k + k\) and \(n+k = 5\), the \(n =\)

A. 2

B. 3

C. 5

D. 6

E. 9


As per statement given, n=1.5k
n+k=5
Let's Assume, If k=2; n=3 n+k=5. Sufficient.

n=3; OA is B
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Statement: 2n = 3k
Hence: n = 1.5k
Now, n+k =5
2.5k = 5
Hence k = 2
Therefore, n must be 3
OA is B

Posted from my mobile device
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Dillesh4096
Bunuel
If \(n + n = k+ k + k\) and \(n+k = 5\), the \(n =\)

A. 2

B. 3

C. 5

D. 6

E. 9

2n = 3k or k=2n/3
n+k=5
n+2n/3 = 5
5n/3=5
n=3
Option D

Posted from my mobile device

Hi Dillesh4096,
You got the correct answer but you wrote the wrong option.
N=3 is option B not D. You may want to correct the typo. Thanks.
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stne
Dillesh4096
Bunuel
If \(n + n = k+ k + k\) and \(n+k = 5\), the \(n =\)

A. 2

B. 3

C. 5

D. 6

E. 9

2n = 3k or k=2n/3
n+k=5
n+2n/3 = 5
5n/3=5
n=3
Option B

Posted from my mobile device

Hi Dillesh4096,
You got the correct answer but you wrote the wrong option.
N=3 is option B not D. You may want to correct the typo. Thanks.

Hey. Thanks
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