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If no worker of Company X who worked there last year quit, how many wo

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If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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New post 17 Oct 2018, 00:29
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C
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Question Stats:

77% (01:05) correct 23% (01:17) wrong based on 80 sessions

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If no worker of Company X who worked there last year quit, how many workers does the company have now on its payroll?


(1) Last year the ratio of the number of male workers to the number of female workers was 2 to 5.

(2) Since last year, Company X recruited 300 new male workers and no new female workers, raising the ratio of the number of male workers to the number of female workers to 2 to 3.

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Re: If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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New post 20 Oct 2018, 07:44
1
Statement 1 is clearly insufficient as only ratio is given.

Statement 2 gives the ratio after the addition of 300 new male employees, but no info about the ratio before that. Hence insufficient.

Combining both:

Male:Females = 2:5

After 300 new males ratio becomes 2:3.

Now \(\frac{2x+300}{5x} = \frac{2}{3}\)

Solving gives x as 150.
Total employees = 5x = 5*150 = 750.

C is the answer.
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Re: If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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New post 13 Dec 2018, 04:27
Afc0892 wrote:
Statement 1 is clearly insufficient as only ratio is given.

Statement 2 gives the ratio after the addition of 300 new male employees, but no info about the ratio before that. Hence insufficient.

Combining both:

Male:Females = 2:5

After 300 new males ratio becomes 2:3.

Now \(\frac{2x+300}{5x} = \frac{2}{3}\)

Solving gives x as 150.
Total employees = 5x = 5*150 = 750.

C is the answer.


After trying several times, I always end up getting a different result than you.

We can set up two ratios:

1: M/F = 2/5
Solving for M, we get: 5M = 2F

2: The second ratio we can set up is: (M+300)/F = 2/3
Solving, we get 2F = 3M+900

Setting both equal to each other, we get M equal to 450 and F, after plugging in the value for M, 1125.

450/1125 is equal to 2/5 (as above mentioned in 1:)
adding 300 to 450 leaves us with a ratio of 2/3.

I assume you made a mistake somewhere pal.

Best, gota900
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Re: If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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New post 13 Dec 2018, 06:41
gota900 wrote:
Afc0892 wrote:
Statement 1 is clearly insufficient as only ratio is given.

Statement 2 gives the ratio after the addition of 300 new male employees, but no info about the ratio before that. Hence insufficient.

Combining both:

Male:Females = 2:5

After 300 new males ratio becomes 2:3.

Now \(\frac{2x+300}{5x} = \frac{2}{3}\)

Solving gives x as 150.
Total employees = 5x = 5*150 = 750.


C is the answer.


After trying several times, I always end up getting a different result than you.

We can set up two ratios:

1: M/F = 2/5
Solving for M, we get: 5M = 2F

2: The second ratio we can set up is: (M+300)/F = 2/3
Solving, we get 2F = 3M+900

Setting both equal to each other, we get M equal to 450 and F, after plugging in the value for M, 1125.

450/1125 is equal to 2/5 (as above mentioned in 1:)
adding 300 to 450 leaves us with a ratio of 2/3.

I assume you made a mistake somewhere pal.

Best, gota900


Hey gota900,
Yes, I have done a calculation mistake in finding total employees. But the answer remains the same. :)
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Re: If no worker of Company X who worked there last year quit, how many wo   [#permalink] 13 Dec 2018, 06:41
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