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# If no worker of Company X who worked there last year quit, how many wo

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Math Expert
Joined: 02 Sep 2009
Posts: 55668
If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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17 Oct 2018, 00:29
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Difficulty:

15% (low)

Question Stats:

77% (01:05) correct 23% (01:17) wrong based on 80 sessions

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If no worker of Company X who worked there last year quit, how many workers does the company have now on its payroll?

(1) Last year the ratio of the number of male workers to the number of female workers was 2 to 5.

(2) Since last year, Company X recruited 300 new male workers and no new female workers, raising the ratio of the number of male workers to the number of female workers to 2 to 3.

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Joined: 18 Jul 2018
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Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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20 Oct 2018, 07:44
1
Statement 1 is clearly insufficient as only ratio is given.

Statement 2 gives the ratio after the addition of 300 new male employees, but no info about the ratio before that. Hence insufficient.

Combining both:

Male:Females = 2:5

After 300 new males ratio becomes 2:3.

Now $$\frac{2x+300}{5x} = \frac{2}{3}$$

Solving gives x as 150.
Total employees = 5x = 5*150 = 750.

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Joined: 15 Aug 2018
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GMAT 1: 740 Q47 V45
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Re: If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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13 Dec 2018, 04:27
Afc0892 wrote:
Statement 1 is clearly insufficient as only ratio is given.

Statement 2 gives the ratio after the addition of 300 new male employees, but no info about the ratio before that. Hence insufficient.

Combining both:

Male:Females = 2:5

After 300 new males ratio becomes 2:3.

Now $$\frac{2x+300}{5x} = \frac{2}{3}$$

Solving gives x as 150.
Total employees = 5x = 5*150 = 750.

After trying several times, I always end up getting a different result than you.

We can set up two ratios:

1: M/F = 2/5
Solving for M, we get: 5M = 2F

2: The second ratio we can set up is: (M+300)/F = 2/3
Solving, we get 2F = 3M+900

Setting both equal to each other, we get M equal to 450 and F, after plugging in the value for M, 1125.

450/1125 is equal to 2/5 (as above mentioned in 1:)
adding 300 to 450 leaves us with a ratio of 2/3.

I assume you made a mistake somewhere pal.

Best, gota900
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Re: If no worker of Company X who worked there last year quit, how many wo  [#permalink]

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13 Dec 2018, 06:41
gota900 wrote:
Afc0892 wrote:
Statement 1 is clearly insufficient as only ratio is given.

Statement 2 gives the ratio after the addition of 300 new male employees, but no info about the ratio before that. Hence insufficient.

Combining both:

Male:Females = 2:5

After 300 new males ratio becomes 2:3.

Now $$\frac{2x+300}{5x} = \frac{2}{3}$$

Solving gives x as 150.
Total employees = 5x = 5*150 = 750.

After trying several times, I always end up getting a different result than you.

We can set up two ratios:

1: M/F = 2/5
Solving for M, we get: 5M = 2F

2: The second ratio we can set up is: (M+300)/F = 2/3
Solving, we get 2F = 3M+900

Setting both equal to each other, we get M equal to 450 and F, after plugging in the value for M, 1125.

450/1125 is equal to 2/5 (as above mentioned in 1:)
adding 300 to 450 leaves us with a ratio of 2/3.

I assume you made a mistake somewhere pal.

Best, gota900

Hey gota900,
Yes, I have done a calculation mistake in finding total employees. But the answer remains the same.
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Re: If no worker of Company X who worked there last year quit, how many wo   [#permalink] 13 Dec 2018, 06:41
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