If one number exceeds another number by 13 and the larger number is 3/

Question

If one number exceeds another number by 13 and the larger number is 3/2 times the smaller number, then the smaller number is

A. 13
B. 26
C. 31
D. 39
E. 65

mnav · Answer

Smaller number is 3/2 times the smaller number--> smaller number has 2 as a factor and larger number is multiple of 3 and difference of both is 13
Therefore: smaller number is (13*2)=26 and larger number is (13*3)= 39

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pr3mk5 · Answer

Let the larger number be X and smaller number be Y.
Given: X = Y + 13
and X = 3/2Y -> 1.5Y

sub this value in 1st euqation. 
1.5 Y = Y + 13 -> 0.5 Y = 13 -> y = 26

Option B.

EgmatQuantExpert · Answer

Solution

Given:  
 • One number exceeds another number by 13
• Larger number is  \frac{3}{2}  time the smaller number

To find:  
 • The value of the smaller number

Approach and Working:   
If we assume the smaller number to be n, 
 • Then the larger number =  \frac{3n}{2}

As the larger number is 13 more than the smaller number, we can say
 •  \frac{3n}{2} – n = 13 
Or,  \frac{n}{2} = 13 
Or, n = 26 
 
Hence, the correct answer is option B.

Answer: B

KSBGC · Answer

Let the smaller number be x
so, larger no will be x+13

Translate the question we can form an equation:

x+13 = (3/2)x
2x+26=3x
x=26.

Thus the correct answer is Option B.

dhruvin917 · Answer

Translate:

y = x + 13 & y = (3/2)(x)

Solve:

(3/2)x = x + 13
3x = 2x + 26
x = 26

Answer:   B

KanishkM · Answer

Keyword : exceeds another number by 13

x greater number, y smaller number

x = y +13

x = 3/2 y

Putting back the value => 3/2 y - y = 13

y = 26

B

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If one number exceeds another number by 13 and the larger number is 3/

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If one number exceeds another number by 13 and the larger number is 3/

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