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If one number exceeds another number by 13 and the larger number is 3/

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Bunuel
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If one number exceeds another number by 13 and the larger number is 3/ [#permalink] New post   08 Jun 2018, 11:48
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If one number exceeds another number by 13 and the larger number is 3/2 times the smaller number, then the smaller number is

A. 13
B. 26
C. 31
D. 39
E. 65
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B
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Re: If one number exceeds another number by 13 and the larger number is 3/ [#permalink] New post   08 Jun 2018, 12:06
Bunuel wrote:
If one number exceeds another number by 13 and the larger number is 3/2 times the smaller number, then the smaller number is

A. 13
B. 26
C. 31
D. 39
E. 65
Smaller number is 3/2 times the smaller number--> smaller number has 2 as a factor and larger number is multiple of 3 and difference of both is 13
Therefore: smaller number is (13*2)=26 and larger number is (13*3)= 39

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Re: If one number exceeds another number by 13 and the larger number is 3/ [#permalink] New post   08 Jun 2018, 12:14
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Let the larger number be X and smaller number be Y.
Given: X = Y + 13
and X = 3/2Y -> 1.5Y

sub this value in 1st euqation.
1.5 Y = Y + 13 -> 0.5 Y = 13 -> y = 26

Option B.
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Re: If one number exceeds another number by 13 and the larger number is 3/ [#permalink] New post   08 Jun 2018, 12:22
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Solution



Given:
    • One number exceeds another number by 13
    • Larger number is \(\frac{3}{2}\) time the smaller number

To find:
    • The value of the smaller number

Approach and Working:
If we assume the smaller number to be n,
    • Then the larger number = \(\frac{3n}{2}\)

As the larger number is 13 more than the smaller number, we can say
    • \(\frac{3n}{2} – n = 13\)
    Or, \(\frac{n}{2} = 13\)
    Or, n = 26

Hence, the correct answer is option B.

Answer: B
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Re: If one number exceeds another number by 13 and the larger number is 3/ [#permalink] New post   10 Jun 2018, 11:31
Bunuel wrote:
If one number exceeds another number by 13 and the larger number is 3/2 times the smaller number, then the smaller number is

A. 13
B. 26
C. 31
D. 39
E. 65



Let the smaller number be x
so, larger no will be x+13

Translate the question we can form an equation:

x+13 = (3/2)x
2x+26=3x
x=26.

Thus the correct answer is Option B.
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dhruvin917
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Re: If one number exceeds another number by 13 and the larger number is 3/ [#permalink] New post   11 Jun 2018, 18:47
Bunuel wrote:
If one number exceeds another number by 13 and the larger number is 3/2 times the smaller number, then the smaller number is

A. 13
B. 26
C. 31
D. 39
E. 65


Translate:

y = x + 13 & y = (3/2)(x)

Solve:

(3/2)x = x + 13
3x = 2x + 26
x = 26

Answer: B
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Re: If one number exceeds another number by 13 and the larger number is 3/ [#permalink] New post   06 Feb 2019, 22:30
Bunuel wrote:
If one number exceeds another number by 13 and the larger number is 3/2 times the smaller number, then the smaller number is

A. 13
B. 26
C. 31
D. 39
E. 65


Keyword : exceeds another number by 13

x greater number, y smaller number

x = y +13

x = 3/2 y

Putting back the value => 3/2 y - y = 13

y = 26

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Re: If one number exceeds another number by 13 and the larger number is 3/ [#permalink]
06 Feb 2019, 22:30
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