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If one of the followings is the product of the two 3-digit integers 8K

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Bunuel
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If one of the followings is the product of the two 3-digit integers 8K [#permalink] New post   10 Jun 2019, 02:11
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If one of the followings is the product of the two 3-digit integers 8K7 and 6L9 (K and L denote the tens digit of the respective integers), then that product must be

(A) 478,823
(B) 511,913
(C) 531,875
(D) 538,424
(E) 569,114
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B
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Re: If one of the followings is the product of the two 3-digit integers 8K [#permalink] New post   10 Jun 2019, 02:16
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Bunuel wrote:
If one of the followings is the product of the two 3-digit integers 8K7 and 6L9 (K and L denote the tens digit of the respective integers), then that product must be

(A) 478,823
(B) 511,913
(C) 531,875
(D) 538,424
(E) 569,114


8K7*6L9

--> Unit digit is 3
So, down to option (1) or (2)

But, a multiple of 8K7*6L9 will be at least 480000.
--> So, Option A is eliminated

Option B

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Re: If one of the followings is the product of the two 3-digit integers 8K [#permalink] New post   04 Jul 2019, 19:02
Seems like a great question for a guess and check option.

8K7 * 6L9 I just make it 807*609 which equals 491,463

This shows two things, one is that the number cannot be smaller than 491,000 and that the units digit will always be 3. Therefore the only answer left available is B
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Re: If one of the followings is the product of the two 3-digit integers 8K [#permalink]
04 Jul 2019, 19:02
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