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E
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Difficulty:
5%
(low)
Question Stats:
97% (00:49) correct
3%
(01:24)
wrong
based on 94
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If P is a positive integer and Q = 120P – 60, which of the following MUST be a divisor of Q?
A. 7
B. 11
C. 13
D. 17
E. 30
A. 7
B. 11
C. 13
D. 17
E. 30
20 Jan 2026, 08:12
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ExpertsGlobal5
Given that P>0 as it’s a positive integer.
Q = 120P – 60
taking 60 as common, we get
Q = 60*(2P-1)
for Q to be divisible, any factor of 60 will be good enough.
factors of 60 = 2*3*2*5= 2^2*3*5, we get 12 factors.
Say: 1,2,3,4,5,6,10,12,15,20,30,60.
Among the options given, 30 matches.
Option E
