Bunuel wrote:

If p is an integer, then p is divisible by how many positive integers?

(1) p = 2^x, where x is a prime number.

(2) p = x^2, where x is a prime number.

St1:- p = 2^x, where x is a prime number

Possible values of p: \(2^2,2^3,2^5,2^7\)

No of factors of p: 3,4,6,8 etc.

Insufficient

St2:- p = x^2, where x is a prime number

Here x can't be factorized further and power of x is a constant.

Hence, the no of factors is constant i.e, 3.

Sufficient.

Ans. (B)

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PKN

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