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If p pounds of beef cost d dollars, how many cents would k pounds of
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Bunuel
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If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink] New post  22 May 2020, 10:11
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If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?


A. \((\frac{d - cp}{p})k\)

B. \((\frac{d - cp}{100p})k\)

C. \((\frac{d - 100cp}{100p})k\)

D. \((\frac{100d - cp}{p})k\)

E. \((\frac{100d - 100cp}{p})k\)



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Re: If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink] New post  22 May 2020, 11:12
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Bunuel wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?


A. \((\frac{d - cp}{p})k\)

B. \((\frac{d - cp}{100p})k\)

C. \((\frac{d - 100cp}{100p})k\)

D. \((\frac{100d - cp}{p})k\)

E. \((\frac{100d - 100cp}{p})k\)



PS20402


    Cost of p pounds of beef = $ d = 100*d cents.
      Cost of one pound = \(\frac{100*d}{p}\) cents.
      New cost of each pound = \(\frac{100*d}{p} – c = \frac{(100d-cp)}{p}\) cents
    Cost of k pounds = \(\frac{(100d-cp)*k}{p}\)
Answer: Option D.
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Re: If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink] New post  22 May 2020, 18:38
$ rate per pound of beef ; d/p
and in cents ; 100*d/p
after c cents reduction ; new rate ; 100d/p - c
and for k pounds rate shall be \((\frac{100d - cp}{p})k\)
OPTION D

Bunuel wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?


A. \((\frac{d - cp}{p})k\)

B. \((\frac{d - cp}{100p})k\)

C. \((\frac{d - 100cp}{100p})k\)

D. \((\frac{100d - cp}{p})k\)

E. \((\frac{100d - 100cp}{p})k\)



PS20402
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If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink] New post  28 Nov 2020, 13:55
1
Kudos
Bunuel wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?


A. \((\frac{d - cp}{p})k\)

B. \((\frac{d - cp}{100p})k\)

C. \((\frac{d - 100cp}{100p})k\)

D. \((\frac{100d - cp}{p})k\)

E. \((\frac{100d - 100cp}{p})k\)



PS20402


\(p\) \(pounds = d \) \(dollars\)

\(p pounds = 100d cents\)

Reduction = c * p (c cents multiplied by the number of pounds)

How many cents would k pounds of beef cost after the price had been reduced by c cent per pounds?

\(( \frac{100d - cp}{p} ) * k\)

Answer is D.
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If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink]
28 Nov 2020, 13:55
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