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# If p pounds of beef cost d dollars, how many cents would k pounds of

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If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink]
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Bunuel wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?

A. $$(\frac{d - cp}{p})k$$

B. $$(\frac{d - cp}{100p})k$$

C. $$(\frac{d - 100cp}{100p})k$$

D. $$(\frac{100d - cp}{p})k$$

E. $$(\frac{100d - 100cp}{p})k$$

PS20402

$$p$$ $$pounds = d$$ $$dollars$$

$$p pounds = 100d cents$$

Reduction = c * p (c cents multiplied by the number of pounds)

How many cents would k pounds of beef cost after the price had been reduced by c cent per pounds?

$$( \frac{100d - cp}{p} ) * k$$

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Re: If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink]
Bunuel wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?

A. $$(\frac{d - cp}{p})k$$

B. $$(\frac{d - cp}{100p})k$$

C. $$(\frac{d - 100cp}{100p})k$$

D. $$(\frac{100d - cp}{p})k$$

E. $$(\frac{100d - 100cp}{p})k$$

PS20402

BrentGMATPrepNow any idea why these numbers dont work
D = 2
P=2
K=3
C=0.5
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If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink]
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dave13 wrote:
Bunuel wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?

A. $$(\frac{d - cp}{p})k$$

B. $$(\frac{d - cp}{100p})k$$

C. $$(\frac{d - 100cp}{100p})k$$

D. $$(\frac{100d - cp}{p})k$$

E. $$(\frac{100d - 100cp}{p})k$$

PS20402

BrentGMATPrepNow any idea why these numbers dont work
D = 2
P=2
K=3
C=0.5

Those numbers work (although c = 0.5 means the price per pound has been reduced by 0.5 cents, which is kind of strange but irrelevant
When we input those values, the answer is 298.5.
In other words, k pounds of beef will cost 298.5 cents

When we plug the 4 values into each answer choice, only D evaluates to be 298.5
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Re: If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink]
Asked: If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?

Price per pound of beef = d/p
Price after reduction of c cents per pound = (d/p - c/100)
Price in cents of k pounds of beef after price reduction = k100(d/p - c/100) = k/p (100d - cp)

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Re: If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink]
Bunuel wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?

A. $$(\frac{d - cp}{p})k$$

B. $$(\frac{d - cp}{100p})k$$

C. $$(\frac{d - 100cp}{100p})k$$

D. $$(\frac{100d - cp}{p})k$$

E. $$(\frac{100d - 100cp}{p})k$$

PS20402

The price of beef in dollars, per pound, is d/p. In cents, the price per pound is 100d/p. When we reduce the price by c cents per pound, we have:

100d/p - cp/p = (100d - cp)/p

Thus, k pounds costs:

k(100d - cp)/p

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Re: If p pounds of beef cost d dollars, how many cents would k pounds of [#permalink]
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