If p, q, r are a series of three consecutive positive integers, is the

Question

Tough and Tricky questions: Number Properties.

If p, q, r are a series of three consecutive positive integers, is the sum of all the integers odd?

(1) Two of the three numbers p, q, r are odd numbers.
(2) (p + q + r)/3 is an even integer.

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hopeful101candidate · Answer

If p, q, r are a series of three consecutive positive integers, is the sum of all the integers odd?

(1) Two of the three numbers p, q, r are odd numbers.

Pick numbers (realize you have to start with an odd integer since you need two odd):

p = 1, q = 2, r = 3; sum = 1 + 2 + 3 = 6 (even) NO

odd + even + odd = always even

Statement 1 is sufficient to answer the question alone.

(2) (p + q + r)/3 is an even integer.

Realize that you need the numerator to be even since only even/odd = even; odd/odd = odd. Therefore, p + q + r = even.

Statement 2 is sufficient to answer the question alone.

Answer is D.

Ankur9 · Answer

(1) Two of the three numbers p, q, r are odd numbers.
sum of 3 consecutive numbers in which 2 are even will always be even  
sufficient

(2) (p + q + r)/3 is an even integer.
let p = n-1
q = n
r = n+1
then p+q+r = 3n
(p + q + r)/3 = n= even then 3n will always be even
sufficient

in both the options the answer to the question is that sum of all the integers is not odd

intheend14 · Answer

From the premise, we're trying to determine if we have o, e, o or e, o, e for the three integers. If the first integer is even, the sum is odd and if the first integer is odd, the sum is even.

From statement 1: two are odd, meaning we have odd, even, odd--sum = even. Sufficient.
From statement 2: basically the same thing, sum/3 = even, so sum must be even. Sufficient.

Choose D

kinghyts · Answer

Statement 1: two of the three numbers p, q, r are odd numbers.

The series can be represented as : 2n+1, 2n+2, 2n+3

Sum = 6n + 6 = 2*(n+3) . Sufficient, since any integer multiplied by 2 yields an even integer.

Statement 2: (p + q + r)/3 is an even integer.

therefore, p + q + r = 3*2*n

Sufficient, since any integer multiplied by 2 yields an even integer.

Answer should be D)

82vkgmat · Answer

Answer D.
1) IF 2 integers are odd, then third is even, so sum is even. SUFFICIENT.
2) If average is even, then 2 integers are odd, so sum is even. SUFFICIENT.

Answer = D.

Bunuel · Answer

Yes, the correct answer is D.

bumpbot · Answer

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If p, q, r are a series of three consecutive positive integers, is the

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