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how can r^2+r/s be an odd positive integer at first place? just wondering!

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Tridhipal
If r and s are positive integers, and \(r^{2} + r/s\) is an odd integer, which of the following cannot be even?

A.\(3r + 2s\)

B.\((r-1)(s+2)\)

C.\(r^{s+1} + s^r\)

D.\(r^{3} +3\)

E.\(s^{4} +4\)

\(r^{2} + \frac{r}{s}=Odd\), So there are two scenarios -

Case 1: \(r^2=Odd\) and \(\frac{r}{s}=Even\). Now if \(r\) is \(Odd\) then \(s\) has to be \(Odd\) and \(\frac{Odd}{Odd}\) cannot be \(Even\). Hence this case is invalid

Case 2: \(r^2=Even\) and \(\frac{r}{s}=Odd\)

\(=>s*Odd=r=Even\). hence \(s\) has to be \(Even\).

Now looking at the options only Option \(D\) cannot be even because Option \(D\) translates into

\(Even+Odd=Odd\)

Option D
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umangsharma94
how can r^2+r/s be an odd positive integer at first place? just wondering!

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Hi umangsharma94

yes it can be

for eg. if r=s=2, then the equation becomes 4+1=5=odd
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nailin16
it can be B too...
why not B

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Hi nailin16

first you need to ascertain the property of \(r\) & \(s\) here. Once you know that both are Even then Option B translates into -

(even-odd)*(even+even)=even
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umangsharma94
how can r^2+r/s be an odd positive integer at first place? just wondering!

Sent from my ONEPLUS A5010 using GMAT Club Forum mobile app

Hi umangsharma94

yes it can be

for eg. if r=s=2, then the equation becomes 4+1=5=odd
Yeah, i actually got it a bit late after I replied! Thanks :)

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Tridhipal
If r and s are positive integers, and \(r^{2} + r/s\) is an odd integer, which of the following cannot be even?

A.\(3r + 2s\)

B.\((r-1)(s+2)\)

C.\(r^{s+1} + s^r\)

D.\(r^{3} +3\)

E.\(s^{4} +4\)


Given \(r^{2} + r/s\) - is an Odd Integer

implies that \(r/s\) is odd & \(r\) is even, since Odd/Even cannot be an integer.

Hence Answer D. \(r^{3} +3\) cannot be even.

Thanks,
GyM
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