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vermatanya
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It should be 'C'.

Stmt1: 2R is evenly divisible by 3.
R = 0, 3, 6, 9, 12, 15,....

R = 3 is NOT evenly div by 3 but R =6 is.

So INSUFF.

Stmt2: 3R is evenly div by 3.
That means R should be even.

R = 0, 2, 4, 6, 8,......

R = 2 is not div by 3 but R =6 is
So INSUFF

Taking them together
Values of R satisfying both the conditions are R = 0, 6, 12, ....
So R is evenly div by 3.
Hence SUFF.

Please share the OA.
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vshaunak@gmail.com
It should be 'C'.

Stmt1: 2R is evenly divisible by 3.
R = 0, 3, 6, 9, 12, 15,....

R = 3 is NOT evenly div by 3 but R =6 is.

So INSUFF.

Stmt2: 3R is evenly div by 3.
That means R should be even.

R = 0, 2, 4, 6, 8,......

R = 2 is not div by 3 but R =6 is
So INSUFF

Taking them together
Values of R satisfying both the conditions are R = 0, 6, 12, ....
So R is evenly div by 3.
Hence SUFF.

Please share the OA.


I think there's some confusion here driven by the unfortunate wording "evenly divisible," which just means divisible--in fact, my impression is GMAT doesn't use it because it's redundant.

If the question were asking whether R yields an even integer when divided by 3 (or, in other words, whether R is divisible by 6), the answer is C: from 1 we know only that R has a factor of 3, from II that it has a factor of 2, and so both together work. But the question would have to be worded differently to mean this.
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vermatanya
if R is an integer , is R evenly divisible by 3?

(1) 2R is evenly divisible by 3.
(2) 3R is evenly divisible by 3.


A. since R is an integer, if 2R is divided by 3, then R is also divided by 2.

so its A.



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