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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
S=[.....5....]

Statment 1:
5+5,
=>5+5+5 and so on for all =ve multiples of 5
S=[5,10,15,.........] Not all multiples of 5 but have no clue of other components of S so insuff

stament 2:
5-5
S=[....10,-5,0,5] Not all multiples of 5 but have no clue of other components of S so insuff


Combining both S= [10,-5,0,5,10,15]

==> AND is C
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
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If S is a set of integers and 5 is in S, is every multiple of 5 in S?

(1) If x is in S, then x+5 is in S. Since 5 is in the set, then 5+5=10, 10+5=15, 15+5=20, ... are also in the set. So, every multiple of 5 more than or equal to 5 are in the set. Though we cannot be sure about the multiples of 5 less than 5 (0, -5, ...). Not sufficient.

(2) If x is in S, then x-5 is in S. The same here: 5, 0, -5, -10, are also in the set. We don't know whether the multiples of 5 which are greater thatn 5 are also in the set. Not sufficient.

(1)+(2) All multiples of 5 are in the set. Sufficient.

Answer: C.

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Hope it helps.
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
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Hi ..one question..
Why can't we assume x to be any other integer such as 1,2,3,4,6...
In that case both the condtions will not suffice even after combination..
help plz..
Thanks
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
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aankittcoolest wrote:
Hi ..one question..
Why can't we assume x to be any other integer such as 1,2,3,4,6...
In that case both the condtions will not suffice even after combination..
help plz..
Thanks


Please check the links provided in the post above. Your doubt is answered in that threads many times.

Consider (1): we are told that if some integer (x) is in the set then that integer plus 5 is also in S. This is a property of set S.

We know that 5 is in S, which means that integers 10, 15, 20, ... are also in S. But we cannot assume that there are any other integers in the set apart from these.
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
fozzzy wrote:
If S is a set of integers 5 is in S, is every multiple of 5 in S?

1) If X is in s, then x+5 is in S.
2) if X is in S, then X-5 is in S.


Set with all multiples of 5 shld contain {....-15,-10,-5,0,5,10,15....}

From Stmt 1) 5,10,15,.... will be present in Set S, 1 Alone not sufficient
From Stmt 2) 0,-5,-10,-15....will be present in Set S, 2 Alone not sufficient
Both together can ans the question,,Hence C

Hope its clear
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
So isn't it that x can take any value,
From the first statement the constraint is 5 should be in Set and if x is in the set then x+5 should be in the set:
So x = 0 implies that 0,5,10 ... are in the set
x= -5 implies that -5, 0, 5, 10 ... are in the set
x = -10 implies that -10, -5, 0, 5 ... are in the set
x = -100 implies that -100, -95, -90, -85 ... are in the set
and I think the same logic can be extended till -infinity ... So statement 1 is sufficient.

Same logic goes for statement 2 as well...
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
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This is not a good practice question. The GMAT doesn't test 'negative multiples' of integers, so you'd never see something like this on the real test. GMAT divisibility questions are almost always explicitly restricted to positive integers, and if they're not, you'll get the same answer whether you think about zero and negatives or don't.

A lot of prep companies design questions like this, trying to be 'tricky', but practice questions that sensitize test takers to 'traps' the GMAT would never use are doing test takers a disservice. Any time a test taker spends, during a test, thinking about the 'trap' this question illustrates is time wasted.
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
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Re: If S is a set of integers and 5 is in S, is every multiple [#permalink]
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