If T = 5/9 * (K - 32), and if T = 290, then K =

Question

(A) 1,738/9 
(B) 322 
(C) 490 
(D) 554 
(E) 2,898/5

Bunuel · Accepted Answer

Given that  290=\frac{5}{9} * (K - 32) ;

290*\frac{9}{5}=K - 32 ;

522=K-32 ;

K=554 .

Answer: D.

PareshGmat · Answer

290 = \frac{5}{9} * (k-32)

k = 290*\frac{9}{5} + 32

k = 58*9 + 32

Answer would be ending with 4; only option D = 554 fits in

Answer = D

legitpro · Answer

290=\frac{5}{9}(K-32)
58*9=k-31
i rounded 9 to 10 so 
580-58+31=k
then i choose d, no point in doing calculations to waste time

JimGMATAnswers · Answer

Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...

JeffTargetTestPrep · Answer

We start by substituting 290 for T and we obtain:

290 = 5/9(K – 32)

To eliminate the fraction, we multiply the entire equation by 9 and we have:

290 x 9 = 5(K – 32)

We next divide both sides by 5 and then solve for K:

58 x 9 = K – 32

522 = K – 32

554 = K

The answer is D.

unraveled · Answer

T = \frac{5}{9} * (K - 32) 
As T = 290

290 =  T = \frac{5}{9} * (K - 32) 
Solving we have
58*9 + 32 = K

Here we can see that it would result in 500+ something value so answer should be D.

Beside the unit value of 58*9 + 32 is '4' just in case we need to verify.

Answer D.

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If T = 5/9 * (K - 32), and if T = 290, then K =

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If T = 5/9 * (K - 32), and if T = 290, then K =

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