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If T = 5/9 * (K - 32), and if T = 290, then K =

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If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 07 Dec 2012, 06:48
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Question Stats:

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If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5
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If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 07 Dec 2012, 06:50
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 06 Aug 2013, 23:55
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290=\frac{5}{9}(K-32)
58*9=k-31
i rounded 9 to 10 so
580-58+31=k
then i choose d, no point in doing calculations to waste time
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 03 Sep 2014, 02:30
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\(290 = \frac{5}{9} * (k-32)\)

\(k = 290*\frac{9}{5} + 32\)

k = 58*9 + 32

Answer would be ending with 4; only option D = 554 fits in

Answer = D
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 04:06
Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 04:14
jackrim1 wrote:
Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?


Sure, look below:

Given: T = 5/9 * (K - 32) ----> Multiply both sides by 9/5, we get ----> 9/5T = (5/9 * 9/5) * (K-32)

----> 9/5 * T = 1 * (K-32) ----> (9/5 )T = K -32 (as x*1 = x) ----> Now add 32 to both sides (to transfer 32 from K-32 towards T), we get ----> (9/5)T + 32 = K

Now susbtitute T = 290 in the last equation, we get

(9/5) * 290 + 32 = K ----> K = 9 *58 + 32 = 522 + 32 = 544.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 05:28
Ah they multiplied by the reciprocal, I misunderstood that.

Thanks
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 06:59
Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5


\(290 * 9 = 5 * (K - 32)\)
\(K = \frac{(290*9) + 32}{5}\)
\(K = 554.\) Ans (D).
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 10:18
Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 10:48
Very good point. What's your strategy upon seeing a question such as that and deciding which tactic to use?
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 10:52
Honestly, it is something that you should be looking at most of the time. This is a thinking exam, not at math exam.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 14 Jul 2015, 11:46
True, but if you do attempt to answer a question without doing math then there's a higher risk of getting muddled or making careless errors. There's obviously a balancing act and it'd be preferable to have some sort of guidelines to apply in choosing how to tackle a problem
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 09 Jun 2016, 14:05
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Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5


We start by substituting 290 for T and we obtain:

290 = 5/9(K – 32)

To eliminate the fraction, we multiply the entire equation by 9 and we have:

290 x 9 = 5(K – 32)

We next divide both sides by 5 and then solve for K:

58 x 9 = K – 32

522 = K – 32

554 = K

The answer is D.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 27 Aug 2017, 03:49
i tried to do this way and got the answer wrong.please tell me where did I go wrong.


290 * 9 = 5k - 160
k = 2610/5
k = 522
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 27 Aug 2017, 04:06
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 09 Oct 2017, 14:04
JimGMATAnswers wrote:
Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...


Just to jump in here - how do we exactly know that what we're working with is a whole number?

Thanks!
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 28 Feb 2018, 09:37
Bunuel wrote:
Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5


Given that \(290=\frac{5}{9} * (K - 32)\) --> \(290*\frac{9}{5}=K - 32\) --> \(522=K-32\) --> \(K=554\).

Answer: D.


hi Bunuel,

i used arithmetic method to solve it, but it took long time.

can you explain based on which rule you you divided both parts by 5/9 ?

i revied all kinds of agebra articles but still encounter such simple gaps :)
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Re: If T = 5/9 * (K - 32), and if T = 290, then K =  [#permalink]

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New post 18 Mar 2018, 07:03
Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5


T = 5/9 * (K - 32)

T = 290

means 290 = 5/9 * (K - 32)

(290 * 9) / 5 = K - 32

K = 522 + 32

K = 554

Hence (D)
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = &nbs [#permalink] 18 Mar 2018, 07:03
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