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If T = 5/9 * (K  32), and if T = 290, then K =
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07 Dec 2012, 06:48
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If T = 5/9 * (K  32), and if T = 290, then K = (A) 1,738/9 (B) 322 (C) 490 (D) 554 (E) 2,898/5
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If T = 5/9 * (K  32), and if T = 290, then K =
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07 Dec 2012, 06:50
Walkabout wrote: If T = 5/9 * (K  32), and if T = 290, then K =
(A) 1,738/9 (B) 322 (C) 490 (D) 554 (E) 2,898/5 Given that \(290=\frac{5}{9} * (K  32)\); \(290*\frac{9}{5}=K  32\); \(522=K32\); \(K=554\). Answer: D.
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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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06 Aug 2013, 23:55
290=\frac{5}{9}(K32) 58*9=k31 i rounded 9 to 10 so 58058+31=k then i choose d, no point in doing calculations to waste time



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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03 Sep 2014, 02:30
\(290 = \frac{5}{9} * (k32)\)
\(k = 290*\frac{9}{5} + 32\)
k = 58*9 + 32
Answer would be ending with 4; only option D = 554 fits in
Answer = D



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 04:06
Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 04:14
jackrim1 wrote: Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd? Sure, look below: Given: T = 5/9 * (K  32) > Multiply both sides by 9/5, we get > 9/5T = (5/9 * 9/5) * (K32) > 9/5 * T = 1 * (K32) > (9/5 )T = K 32 (as x*1 = x) > Now add 32 to both sides (to transfer 32 from K32 towards T), we get > (9/5)T + 32 = K Now susbtitute T = 290 in the last equation, we get (9/5) * 290 + 32 = K > K = 9 *58 + 32 = 522 + 32 = 544.



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 05:28
Ah they multiplied by the reciprocal, I misunderstood that.
Thanks



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 06:59
Walkabout wrote: If T = 5/9 * (K  32), and if T = 290, then K =
(A) 1,738/9 (B) 322 (C) 490 (D) 554 (E) 2,898/5 \(290 * 9 = 5 * (K  32)\) \(K = \frac{(290*9) + 32}{5}\) \(K = 554.\) Ans (D).
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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 10:18
Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...
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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 10:48
Very good point. What's your strategy upon seeing a question such as that and deciding which tactic to use?



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 10:52
Honestly, it is something that you should be looking at most of the time. This is a thinking exam, not at math exam.
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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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14 Jul 2015, 11:46
True, but if you do attempt to answer a question without doing math then there's a higher risk of getting muddled or making careless errors. There's obviously a balancing act and it'd be preferable to have some sort of guidelines to apply in choosing how to tackle a problem



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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09 Jun 2016, 14:05
Walkabout wrote: If T = 5/9 * (K  32), and if T = 290, then K =
(A) 1,738/9 (B) 322 (C) 490 (D) 554 (E) 2,898/5 We start by substituting 290 for T and we obtain: 290 = 5/9(K – 32) To eliminate the fraction, we multiply the entire equation by 9 and we have: 290 x 9 = 5(K – 32) We next divide both sides by 5 and then solve for K: 58 x 9 = K – 32 522 = K – 32 554 = K The answer is D.
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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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27 Aug 2017, 03:49
i tried to do this way and got the answer wrong.please tell me where did I go wrong.
290 * 9 = 5k  160 k = 2610/5 k = 522



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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27 Aug 2017, 04:06
santro789 wrote: i tried to do this way and got the answer wrong.please tell me where did I go wrong.
290 * 9 = 5k  160 k = 2610/5 k = 522 290*9 + 160 = 2770, not 2610.
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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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09 Oct 2017, 14:04
JimGMATAnswers wrote: Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that... Just to jump in here  how do we exactly know that what we're working with is a whole number? Thanks!



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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28 Feb 2018, 09:37
Bunuel wrote: Walkabout wrote: If T = 5/9 * (K  32), and if T = 290, then K =
(A) 1,738/9 (B) 322 (C) 490 (D) 554 (E) 2,898/5 Given that \(290=\frac{5}{9} * (K  32)\) > \(290*\frac{9}{5}=K  32\) > \(522=K32\) > \(K=554\). Answer: D. hi Bunuel, i used arithmetic method to solve it, but it took long time. can you explain based on which rule you you divided both parts by 5/9 ? i revied all kinds of agebra articles but still encounter such simple gaps



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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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18 Mar 2018, 07:03
Walkabout wrote: If T = 5/9 * (K  32), and if T = 290, then K =
(A) 1,738/9 (B) 322 (C) 490 (D) 554 (E) 2,898/5 T = 5/9 * (K  32) T = 290 means 290 = 5/9 * (K  32) (290 * 9) / 5 = K  32 K = 522 + 32 K = 554 Hence (D)
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Re: If T = 5/9 * (K  32), and if T = 290, then K =
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13 Sep 2019, 23:40
Walkabout wrote: If T = 5/9 * (K  32), and if T = 290, then K =
(A) 1,738/9 (B) 322 (C) 490 (D) 554 (E) 2,898/5 Given: 1. T = 5/9 * (K  32) 2. T = 290 Asked: K = ? 290 = 5/9 * (K32) K  32 = 290 * 9/5 = 58*9 = 522 K = 32 + 522 = 554 IMO D




Re: If T = 5/9 * (K  32), and if T = 290, then K =
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13 Sep 2019, 23:40






