akankshaboparai
Hi, Lets assume t=48 and if we try to solve it, it is divisible by 2^5. Can you please explain why this is happening?
Hi
akankshaboparai,
Question stem:- what is the
least possible integer value of a for which \(\frac{t^2}{2^a}\)
MIGHT NOT be an integer?
1) We have been asked to find the
least possible integer value of 'a'.
2) As assumed, at t=48 and a=5, the given fraction is an integer.
(Correct, but least possible value of 'a' would be obtained when 't' is the minimum. ).
Does a=5 produce integer values of the fraction at all 't'? NO (Discard this scenario)
3) Here t=12k, k is a positive integer.
4) So we have to check at t=12*1=12 (At minimum 't')
\(\frac{12^2}{2^a}\)=\(\frac{2^4*3^2}{2^a}\) doesn't yield an integer at a=5 and 6. But it yields integers at a=1,2,3, and 4.
Between 5 and 6, 5 is the least possible value.
Hope it helps.