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If the average (arithmetic mean) monthly sales of a department store w

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If the average (arithmetic mean) monthly sales of a department store w  [#permalink]

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New post 07 Jun 2017, 04:18
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If the average (arithmetic mean) monthly sales of a department store was y dollars during a certain period of several years, what is the average biannual sales over the same period?

(1) The period includes exactly 4 years.
(2) y = 500.

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Re: If the average (arithmetic mean) monthly sales of a department store w  [#permalink]

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New post 07 Jun 2017, 08:23
duahsolo wrote:
If the average (arithmetic mean) monthly sales of a department store was y dollars during a certain period of several years, what is the average biannual sales over the same period?

(1) The period includes exactly 4 years.
(2) y = 500.



total sales/ N (no. of months ) = y (given)

then total sales =???

(1) n= 48 (12*4=48)
not suff..

(2) y =500
n=2(biannual) *12 = 24

total sales = 500*24

suff

Ans B
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Re: If the average (arithmetic mean) monthly sales of a department store w  [#permalink]

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New post 05 Jul 2017, 13:58
rohit8865 wrote:
duahsolo wrote:
If the average (arithmetic mean) monthly sales of a department store was y dollars during a certain period of several years, what is the average biannual sales over the same period?

(1) The period includes exactly 4 years.
(2) y = 500.



total sales/ N (no. of months ) = y (given)

then total sales =???

(1) n= 48 (12*4=48)
not suff..

(2) y =500
n=2(biannual) *12 = 24

total sales = 500*24

suff

Ans B


How is 'n=2' multiplied by 12 in statement (2)?
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New post 08 Jul 2017, 12:18
Given:
Total sales = s
Average monthly sales over x years = s/(12x) = y
Bi-annual means 2*x (in denominator). Therefore, question is asking what is s/(2x)?

1) x=4
s/(2*4)=s/8 --> not sufficient.

2) y=500
s/(12x) = 500
s = 6000x
s/(2x) = 6000x/2x = 3000. Hence sufficient.

Please correct me if I'm wrong.
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New post 09 Jul 2017, 00:54
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rohit8865 wrote:
total sales/ N (no. of months ) = y (given)

then total sales =???

(1) n= 48 (12*4=48)
not suff..

(2) y =500
n=2(biannual) *12 = 24

total sales = 500*24

suff

Ans B


Hey rohit8865 ,

There is a problem in your solution. I have highlighted the same.

Total sale for x years = y * 12 * x

Biannual years means total years/2 = x/2

Average sale for biannual years = Total sale for x years/ number of biannual years = y *12 *x/2x = 6y.

Now, option B tells us the value of y, hence we can find out the average sale for biannual years. Hence, option B is sufficient.

TheMastermind wrote:
How is 'n=2' multiplied by 12 in statement (2)?


Hi TheMastermind ,

y is average monthly sale. Therefore to get annual sale, we are multiplying it with 12.

I hope that makes sense. :)
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New post 09 Jul 2017, 20:26
First, make sure what the question asks: what is the average biannual sales over the same period?

It means, let's figure out average sales in a 6-month basis over the same period: 6y.
Why? Let's call x: the number of years in that period --> Total sales in the period: 12xy
--> Average biannual sales: (12xy/2x) = 6y

Therefore, if we know value of y, surely we'll get the answer.

Now look at the statements

(1) The period includes exactly 4 years.
x=4. However, y is unknown. Depending on particular values of y, we will get different results of 6y
Inconsistent answers. Insufficient statement.

ELIMINATE (A) and (D)

(2) y = 500.
--> Average biannual sales: 6y = 6x500=3,000
Sufficient statement.

(B) IS CORRECT!
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If the average (arithmetic mean) monthly sales of a department store w   [#permalink] 09 Jul 2017, 20:26
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