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# If the average (arithmetic mean) of 5 positive temperatures

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The sum of three greatest should be more than sum of two lowest.

The total sum is; 5x

A. 6x; 6x is more than 5x. Not possible.
B. 4x; 5x-4x=x(Possible)
C. 5x/3; 10x/3; 10x/3 > 5x/3. Not possible
D. 3x/2; 7x/2; 7x/2 > 3x/2. Not possible
E. 3x/5; 22x/5; 22x/5 > 3x/5. Not possible.

Ans: "B"
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Temperatures should be positive.
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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
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If the average (arithmetic mean) of 5 positive temperatures is x degrees Fahrenheit, then the sum of the 3 greatest of these temperatures, in degrees Fahrenheit, could be:

A. 6x
B. 4x
C. 5x/3
D. 3x/2
E. 3x/5

Responding to a pm:

Avg of 5 temperatures is x. So the sum of all 5 temperatures is 5x.
Now what CAN be the sum of the 3 greatest temperatures?

Let's try to find the maximum value that the 'sum of the 3 greatest temperatures' can take and the minimum value that it can take.

Maximum: To make the sum of 3 greatest temperatures as large as possible, we make the 2 lowest temperatures as small as possible. The two lowest temperatures can be as small as 0.0000000000000001 i.e. anything slightly more than 0. So the sum of the 3 greatest temperatures will be slightly less than 5x.

Minimize: To minimize the sum of 3 greatest temperatures, we make the 2 lowest temperatures as high as possible. For the average to be x, either some values should be less than x and some more OR all values could be equal to x. That is, the temperatures could be x, x, x, x, x - in this case the two lowest temperatures are maximum (all temperatures are the same actually). So sum of 3 greatest temperatures will be at least 3x.

Note that only one value lies between 5x and 3x and that is 4x.

We don't really need to figure out the minimum sum. Once we know that maximum sum can be a little less than 5x, we see that the sum of 3 greatest temperatures can easily be 4x. We will be left with a sum of x for the two lowest temperatures. They can be x/2 each. The 3 greatest temperatures can be x, x and 2x or many other variations.
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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
Hi All,

One of the great 'shortcuts' to this question is that it asks for what COULD be the sum of the three highest temperatures. As such, once you find an answer that COULD be the sum, you can STOP working. Once you prove that Answer is a possibility, then you've answered the question (and you can stop).

GMAT assassins aren't born, they're made,
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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
let x be 2 and total sum becomes 10
now using maximization and minimization the least values can be 1 and 1 equaling to 2 =>10-2 = 8 (rest of the temp)

substituting x in the options gives the answer B
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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
Great Question.
I actually didnt solve it as a maxima minima question
I used brute Force to arrive at his set {x/2,x/2,4x/3,4x/3,4x/3} using Option B.

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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
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Hi All,

This question has a couple of great "concept" shortcuts built into it.

We're told that the average of 5 positive numbers is X, which means that the SUM of the 5 numbers is 5X.

The question asks us for a POSSIBLE sum of the greatest 3 values….

Since the values are all POSITIVE and they sum to 5X, there's no way for the sum of the greatest 3 to be bigger than that. 6X is NOT possible. Eliminate A.

IF all the values were the same (just call them all X), then the biggest 3 would sum to 3X. Changing the values would only INCREASE the sum of the biggest 3. This helps to eliminate C, D and E - they're all too small.

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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
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Re: If the average (arithmetic mean) of 5 positive temperatures [#permalink]
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