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If the average (arithmetic mean) of five consecutive negative integers

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If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 28 Sep 2009, 19:31
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If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 28 Sep 2009, 23:09
tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?


Do we need to know the Average is even or odd to find the range of these 5 neg consecutives?

And Even the five are neg or not, the range is always 4.
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 29 Sep 2009, 11:49
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numbers will be 2k-3, 2k-2, 2k-1, 2k, 2k+1
range = 2k+1 - 2k+3 = 4
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 29 Sep 2009, 21:13
Def. sleep deprived when I was doing the question :shock:
Sorry got thrown off by the negative integer thing..
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 18 May 2011, 00:00
5 consecutive numbers means difference between first and the last integer = 4
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 18 Mar 2019, 18:51
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tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined


We are asking for the range of the 5 consecutive integers. It’s a fact that the range of a set of n integers is always n - 1. For example, in the set of {2, 3, 4, 5, 6, 7}, there are 6 consecutive integers, we see that the range is 7 - 2 = 5, which is 1 less than the number of consecutive integers. Therefore, in a set of 5 consecutive integers, whether they be positive or negative, the difference between the greatest and least integers, i.e., the range, is 4.

Answer: A
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 19 Mar 2019, 06:04
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tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined


Let x = the 1st (smallest integer)
So, x+1 = the 2nd integer
x+2 = the 3rd integer
x+3 = the 4th integer
x+4 = the 5th integer (greatest integer)

What is the difference between the greatest and least of the five integers?
Difference = ( x+4) - x = 4

Answer: A

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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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New post 20 Mar 2019, 09:37
tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined



sum of 5 consective no
5a+10 = 10k-5
a= 2k-3
so largest no ; 4+2k-3
differnrence
4+2k-3-2k+3 = 4
IMO A
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Re: If the average (arithmetic mean) of five consecutive negative integers   [#permalink] 20 Mar 2019, 09:37
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