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# If the average (arithmetic mean) of five consecutive negative integers

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Senior Manager
Joined: 25 Oct 2008
Posts: 444
Location: Kolkata,India
If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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28 Sep 2009, 19:31
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If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined
Intern
Joined: 25 Mar 2009
Posts: 41
Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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28 Sep 2009, 23:09
tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?

Do we need to know the Average is even or odd to find the range of these 5 neg consecutives?

And Even the five are neg or not, the range is always 4.
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Joined: 14 Dec 2008
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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29 Sep 2009, 11:49
1
numbers will be 2k-3, 2k-2, 2k-1, 2k, 2k+1
range = 2k+1 - 2k+3 = 4
Senior Manager
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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29 Sep 2009, 21:13
Def. sleep deprived when I was doing the question
Sorry got thrown off by the negative integer thing..
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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18 May 2011, 00:00
5 consecutive numbers means difference between first and the last integer = 4
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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18 Mar 2019, 18:51
1
tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined

We are asking for the range of the 5 consecutive integers. It’s a fact that the range of a set of n integers is always n - 1. For example, in the set of {2, 3, 4, 5, 6, 7}, there are 6 consecutive integers, we see that the range is 7 - 2 = 5, which is 1 less than the number of consecutive integers. Therefore, in a set of 5 consecutive integers, whether they be positive or negative, the difference between the greatest and least integers, i.e., the range, is 4.

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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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19 Mar 2019, 06:04
1
Top Contributor
tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined

Let x = the 1st (smallest integer)
So, x+1 = the 2nd integer
x+2 = the 3rd integer
x+3 = the 4th integer
x+4 = the 5th integer (greatest integer)

What is the difference between the greatest and least of the five integers?
Difference = ( x+4) - x = 4

Cheers,
Brent
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Re: If the average (arithmetic mean) of five consecutive negative integers  [#permalink]

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20 Mar 2019, 09:37
tejal777 wrote:
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
A)4
B)3
C)2
D)1
E)cannot be determined

sum of 5 consective no
5a+10 = 10k-5
a= 2k-3
so largest no ; 4+2k-3
differnrence
4+2k-3-2k+3 = 4
IMO A
Re: If the average (arithmetic mean) of five consecutive negative integers   [#permalink] 20 Mar 2019, 09:37
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# If the average (arithmetic mean) of five consecutive negative integers

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