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# If the average (arithmetic mean) of three consecutive integers is 2 mo

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Math Expert
Joined: 02 Sep 2009
Posts: 55802
If the average (arithmetic mean) of three consecutive integers is 2 mo  [#permalink]

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26 Nov 2018, 23:58
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Difficulty:

25% (medium)

Question Stats:

77% (01:23) correct 23% (01:47) wrong based on 54 sessions

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If the average (arithmetic mean) of three consecutive integers is 2 more than the average of 18, 27, and 30, what is the greatest of the three consecutive integers?

A. 26
B. 27
C. 28
D. 30
E. 75

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Intern
Joined: 17 Jun 2017
Posts: 44
Re: If the average (arithmetic mean) of three consecutive integers is 2 mo  [#permalink]

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27 Nov 2018, 11:11
Bunuel wrote:
If the average (arithmetic mean) of three consecutive integers is 2 more than the average of 18, 27, and 30, what is the greatest of the three consecutive integers?

A. 26
B. 27
C. 28
D. 30
E. 75

Avg of 18+27+30 / 3 = 25 , Avg is 2 more then 27

n+n+1+n+2/3 = 27
or, 3n=78
n=26
Set (26,27,28) = 28 . I will go with 28 . QA
VP
Joined: 07 Dec 2014
Posts: 1198
If the average (arithmetic mean) of three consecutive integers is 2 mo  [#permalink]

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27 Nov 2018, 13:29
Bunuel wrote:
If the average (arithmetic mean) of three consecutive integers is 2 more than the average of 18, 27, and 30, what is the greatest of the three consecutive integers?

A. 26
B. 27
C. 28
D. 30
E. 75

if the average of three consecutive integers is 27,
the greatest integer must be 27+1=28
C
If the average (arithmetic mean) of three consecutive integers is 2 mo   [#permalink] 27 Nov 2018, 13:29
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