Bunuel wrote:

If the average (arithmetic mean) of three integers is 76, what is the value of the least of the integers?

(1) The median of the integers is 82.

(2) The range of the integers is 54.

Say three integers are a, b, and c in order a < b < c

Given = a + b + c / 3 = 76

a + b+ c = 76 * 3

a + b+ c = 228 -----> (I)

From st 1: b = 82 ------> (II)

Use in (I) a + c = 228 - 82 = 146 (No info about a & c (Insufficient)

From st 2: c - a = 54 -------> (III)

No information about "b" (Insufficient)

Combining 1 & 2 we get

c + a = 146

c - a = 54

c = 100

Cancelling out "a" we get c = 100

Putting c = 100 in any of the three equations we get a = 46 Sufficient (C)

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