Bunuel wrote:

If the average (arithmetic mean) of x, (x+6), (x−4), (x+3), and (x+10) is 21, what is the median of those five numbers?

A. 17

B. 18

C. 19

D. 20

E. 21

The sum of the five numbers is 21*5 = 105.

Therefore x, + (x+6), + (x−4), + (x+3), + (x+10) = 5x +15 = 105.

5x= 105-15 = 90

x= 18.

Therefore the five numbers are:

18, 24, 14, 21, 28. The numbers arranged in ascending order are 14, 18, 21, 24 and 28.

Hence the median and answer is 21 or

option E.
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