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Bunuel
If the average (arithmetic mean) price of apples, bananas and oranges is $3.00 per pound, what is their median price?

(1) The price of apples is $3.00 per pound.
(2) The price of bananas is $2.97 per pound.



(1) The price of apples is $3.00 per pound.

Since price of apples is equal to the avg. itself. Let's see if this CANNOT be the median.

Let \($3.00\) be the highest price.Can we get two other prices lesser than \($3.00\) and the total still add upto \($9\)? NO

Let \($3.00\) be the lowest price.Can we get two other prices greater than \($3.00\) and the total still add upto \($9\)? NO

Hence \($3 \) must be the median.

SUFF.

(2) The price of bananas is $2.97 per pound.

\(2.97,2.97,3.06\)

\(2.97,2.98,3.05\)

\(2.97,3.00,3.03\)...

etc.

INSUFF.

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Thanks!!

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Should we just ignore the number of apples, bananas and oranges and conder all as 1 lot?
stne


(1) The price of apples is $3.00 per pound.

Since price of apples is equal to the avg. itself. Let's see if this CANNOT be the median.

Let \($3.00\) be the highest price.Can we get two other prices lesser than \($3.00\) and the total still add upto \($9\)? NO

Let \($3.00\) be the lowest price.Can we get two other prices greater than \($3.00\) and the total still add upto \($9\)? NO

Hence \($3 \) must be the median.

SUFF.

(2) The price of bananas is $2.97 per pound.

\(2.97,2.97,3.06\)

\(2.97,2.98,3.05\)

\(2.97,3.00,3.03\)...

etc.

INSUFF.

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It's given that average price per pound is xx$ so that means all the 3 prices are averaged out

As the average is 3$ then total should be 9$

So if one of it is 3$ then whatever be the other two extremes, be it equal or have a huge difference, the median will alwys be 3
Advait01
Should we just ignore the number of apples, bananas and oranges and conder all as 1 lot?

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