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If the averages of both sets are equal, what is the value of x?

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Joined: 02 Sep 2009
Posts: 52230
If the averages of both sets are equal, what is the value of x?  [#permalink]

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New post 13 Apr 2018, 02:09
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

93% (01:10) correct 7% (02:43) wrong based on 38 sessions

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Manager
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Joined: 30 May 2017
Posts: 135
Location: United States
Schools: HBS '21
GMAT 1: 690 Q50 V32
GRE 1: Q168 V164
GPA: 3.57
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Re: If the averages of both sets are equal, what is the value of x?  [#permalink]

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New post 13 Apr 2018, 03:17
Bunuel wrote:
Set A={x,x,8,2}
Set B={1,2,2,15,x,x}
If the averages of both sets are equal, what is the value of x?

A. 1
B. 4
C. 5
D. 6
E. 8



(2x+10)/4 = (2x+20)/6

6(2x+10) = 4(2x+20)

12x+60 = 8x+80

4x = 20

x = 5

Hence option C = 5 is the answer.
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Re: If the averages of both sets are equal, what is the value of x?  [#permalink]

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New post 13 Apr 2018, 05:41
[quote="Bunuel"]Set A={x,x,8,2}
Set B={1,2,2,15,x,x}
If the averages of both sets are equal, what is the value of x?

A. 1
B. 4
C. 5
D. 6
E. 8

\(\frac{2x+10}{4}\)= \(\frac{2x+20}{6}\) ==> x=5
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If the averages of both sets are equal, what is the value of x?  [#permalink]

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New post 28 Apr 2018, 17:00
Simply solve

(10+2x)/4=(20+2x)/6

X=5

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If the averages of both sets are equal, what is the value of x? &nbs [#permalink] 28 Apr 2018, 17:00
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If the averages of both sets are equal, what is the value of x?

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