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25 Oct 2007, 15:34
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If the car had traveled 20kmph faster than it actually did, the trip would have lasted 30minutes less. If the car went exactly 60km, what speed did it travel?
Here is my equation and I can't get to the right answer... Where am I making the mistake?
(R+20)(t-1/2)=60
Rt=60
Rt-1/2R+20t -10 =60 ---> Rt-1/2R+20t=70
60-1/2R+20t=70 ---> -1/2R+20t=10 (t=60/R)
-1/2R+20(60/R)=10 ---> 1200/R-R/2=10 --> (2400-R^2)/2R=10
2400-R^2=20R ---> R^2-20R-2400=0 (R-60)(R+40)=0
So R= 60... OA is 40.... what am I doing wrong?
Here is my equation and I can't get to the right answer... Where am I making the mistake?
(R+20)(t-1/2)=60
Rt=60
Rt-1/2R+20t -10 =60 ---> Rt-1/2R+20t=70
60-1/2R+20t=70 ---> -1/2R+20t=10 (t=60/R)
-1/2R+20(60/R)=10 ---> 1200/R-R/2=10 --> (2400-R^2)/2R=10
2400-R^2=20R ---> R^2-20R-2400=0 (R-60)(R+40)=0
So R= 60... OA is 40.... what am I doing wrong?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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25 Oct 2007, 19:00
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GMATBLACKBELT
2400 - R^2 = 20R
R^2 + 20R - 2400 = 0
(R + 60)(R - 40)=0
R = 40
25 Oct 2007, 21:08
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Fistail
I knew it was something so simple, but I just couldn't snuff it out.
Thx
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
