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Bunuel
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Bunuel
If the circumference of circle P is 15.174 and the circumference of circle Q is 6.28, then the diameter of circle P minus the diameter of circle Q is approximately equal to

(A) 1.5
(B) 3.0
(C) 5.5
(D) 9.0
(E) 9.4

Let x be the radius of the circle P and y the radius of the circle Q.

2 * Pi * x = 15.174
2 * Pi * y = 6.28

2x - 2y = 1/Pi * (15.174 - 6.28) = 8.894/3.14 which is approximately 3

Therefore, the difference in diameters of both the circle is 3.0(Option B)

You're correct. I've messed up with radius and diameter :grin:
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