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06 Sep 2021, 06:53
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D
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Difficulty:
5%
(low)
Question Stats:
91% (01:25) correct
9%
(01:56)
wrong
based on 88
sessions
History
Date
Time
Result
Not Attempted Yet
If the cost of p plums priced at 25 cents each equals the cost of p – 6 nectarines priced at 28 cents each, then p equals
A. 26
B. 42
C. 52
D. 56
E. 66
A. 26
B. 42
C. 52
D. 56
E. 66
06 Sep 2021, 06:57
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Bunuel
Given: (the cost of p plums priced at 25 cents) = (the cost of p – 6 nectarines priced at 28 cents each)
Substitute values to get: 25p = 28(p - 6)
Expand the right side to get: 25p = 28p - 168
Subtract 28p from both sides of the equation to get: -3p = -168
Solve: p = (-168)/(-3) = 56
Answer: D
General Discussion
13 Sep 2022, 12:38
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If the cost of p plums priced at 25 cents each equals the cost of p – 6 nectarines priced at 28 cents each, then p equals
A. 26
B. 42
C. 52
D. 56
E. 66
A. 26
B. 42
C. 52
D. 56
E. 66
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