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If the elements of set X are a, b, c and d, is the average (arithmetic

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If the elements of set X are a, b, c and d, is the average (arithmetic [#permalink]

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[GMAT math practice question]

If the elements of set X are a, b, c and d, is the average (arithmetic mean) of a, b, c, and d contained in set X?

1) The average (arithmetic mean) of every pair of elements of set X is 10.
2) The average (arithmetic mean) of every three elements chosen from set X is 10.
[Reveal] Spoiler: OA

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Expert Post
Math Revolution GMAT Instructor
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Joined: 16 Aug 2015
Posts: 5255
GMAT 1: 800 Q59 V59
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Re: If the elements of set X are a, b, c and d, is the average (arithmetic [#permalink]

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New post 15 Apr 2018, 18:40
=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have 4 variables (a, b, c and d) and 0 equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) and 2):
Condition 1) gives rise to the following equations:
\(\frac{( a + b )}{2} = 10 => a + b = 20\)
\(\frac{( a + c )}{2} = 10 => a + c = 20\)

\(\frac{( c + d )}{2} = 10 => c + d = 20\)

Condition 2) gives rise to the following equations:
\(\frac{( a + b + c )}{3} = 10 => a + b + c = 30\)
\(\frac{( a + b + d )}{3} = 10 => a + b + d = 30\)
\(\frac{( a + c + d )}{3} = 10 => a + c + d = 30\)
\(\frac{( b + c + d )}{3} = 10 => b + c + d = 30\)

Combining these equations yields \(a = b = c = d = 10.\)
Therefore, the average is \(10\), which is an element of set X, and conditions 1) and 2) are sufficient, when taken together.

Since this question is a statistics question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.


Condition 1)
Condition 1) gives rise to the following equations:
\(\frac{( a + b )}{2} = 10 => a + b = 20\)
\(\frac{( a + c )}{2} = 10 => a + c = 20\)

\(\frac{( c + d )}{2} = 10 => c + d = 20\)

Combining these equations yields \(a = b = c = d = 10.\)

Condition 2)

Condition 2) gives rise to the following equations:
\(\frac{( a + b + c )}{3} = 10 => a + b + c = 30\)
\(\frac{( a + b + d )}{3} = 10 => a + b + d = 30\)
\(\frac{( a + c + d )}{3} = 10 => a + c + d = 30\)
\(\frac{( b + c + d )}{3} = 10 => b + c + d = 30\)

Combining these equations yields \(a = b = c = d = 10.\)

Therefore, the answer is D.

Answer: D

Since conditions 1) and 2) are equivalent, D is the answer by Tip 1) of the VA method.

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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Re: If the elements of set X are a, b, c and d, is the average (arithmetic   [#permalink] 15 Apr 2018, 18:40
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