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If the integer t is divided by 7, the remainder is 2. If t is divided by 5, the remainder is 3. If t is between 15 and 75, what is the sum of all possible values of t?

(A) 38
(B) 65
(C) 81
(D) 103
(E) 135

Theory: A positive integer a divided by a positive integer d, leaving a remainder of r, can be expressed as \(a = qd + r,\) where q is the quotient and \(0 ≤ r < d\).

If t leaves a remainder of 2 when divided by 7, then t = 7p + 2. So possible values of t are:

2, 9, 16, 23, 30, ...

If t leaves a remainder of 3 when divided by 5, then t = 5q + 3. So possible values of t are:

3, 8, 13, 18, 23, ...

Now we can derive a general formula based on both conditions. In problems of this kind, the combined pattern has the form \(t = dx + r\), where d is the least common multiple of the two divisors and r is the first common value in the two patterns.

Here, the two divisors are 7 and 5, so \(d = LCM(7, 5) = 35\), and the first common value is r = 23. Therefore:

t = 35x + 23

So possible values of t are:

23, 58, 93, ...

The values between 15 and 75 are:

23 and 58

Thus, their sum is:

23 + 58 = 81

Answer: C.
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Other values of t will be obtained by adding the lcm of the divisors i.e. 35
how did you find this?

Because 35 is divisible by 5 and 7 and hence won't leave any extra remainders even if it is added to the number
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