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Joined: 09 Feb 2012
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If the LCM of A and B is 72 and their HCF is 6, what is the
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20 Aug 2012, 11:52
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If the LCM of A and B is 72 and their HCF is 6, what is the product of A & B?Thanks guys!



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Re: If the LCM of A and B is 72 and their HCF is 6, what is the
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20 Aug 2012, 11:57



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Re: If the LCM of A and B is 72 and their HCF is 6, what is the
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01 Oct 2012, 03:09
LCM of two numbers x GDF of the two numbers = Product of the two numbers ... Therefore Product of A and B = 432 ...
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Re: If the LCM of A and B is 72 and their HCF is 6, what is the
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15 Feb 2013, 07:21
Example: You have two numbers x=8 and y=12. LCM of x,y = 24 GCF of x,y = 4 (LCM of x and y) X (GCF of x and y) = XY 24 X 4 = 8 X 12 96 = 96
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Re: If the LCM of A and B is 72 and their HCF is 6, what is the
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15 Feb 2013, 08:14
Product A*B= lcm*hcf(gcd)= 72*6= 423



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Re: If the LCM of A and B is 72 and their HCF is 6, what is the
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15 Feb 2013, 08:49
Try to understand why is so. take two numbers a and b The prime factorization of those numbers is a= d,d,e,r b=d,e,g,h,i HCF of a and b = d,e LCM of a and b = d,e,d,r,g,h,i Product of HCF and LCM = d.e.d.e.d.r.g.h.i > d^3.e^2.r.g.h.i Product of Numbers = d.d.e.r.d.e.g.h.i > d^3.e^2.r.g.h.i in my opinion it is better to understand any theorem/rule than to remember it. Hope it clears! Regards, Abhijit.
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Joined: 28 Apr 2018
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If the LCM of A and B is 72 and their HCF is 6, what is the
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08 Sep 2018, 02:49
The product of any two positive integers x and y is equivalent to the product of the square of their hcf and other individual numbers,or the product of their lcm and hcf. X*Y=HCF^2 * P =LCM*HCF where P is other individual numbers(i.e let's say X = 6:1*2*3 and Y =8:1*2*2*2, the hcf of X and Y is 2 and P is 1*3*1*2*2) therefore X*Y =LCM*HCF= 72*6 =432




If the LCM of A and B is 72 and their HCF is 6, what is the &nbs
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08 Sep 2018, 02:49






