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31 Aug 2021, 03:02
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86% (00:55) correct
14%
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If the length of a rectangle is decreased by 10% and its width is decreased by 20%, by what percent does its area decrease?
A. 30%
B. 28%
C. 25%
D. 23%
E. 15%
A. 30%
B. 28%
C. 25%
D. 23%
E. 15%
Let's say length of the triangle = l
breadth = b
area = l*b
=> After reducing the length by 10%, new length = 0.9*l
=> after reducing the breadth by 20%, new breadth = 0.8*b
=> new area = 0.72*l*b
=> % decrease = \(\frac{(old - new)}{old} = \frac{((1-0.72)*100)}{1} = 28%\)
Option B
breadth = b
area = l*b
=> After reducing the length by 10%, new length = 0.9*l
=> after reducing the breadth by 20%, new breadth = 0.8*b
=> new area = 0.72*l*b
=> % decrease = \(\frac{(old - new)}{old} = \frac{((1-0.72)*100)}{1} = 28%\)
Option B
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31 Aug 2021, 03:07
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Area of rectangle = length * breadth
Area = l*b
New length =0.9 l
New breadth =0.8 b
New area = 0.9l *0.8 b = 0.72 l*b
hence its a 28% decrease
Hence B
Area = l*b
New length =0.9 l
New breadth =0.8 b
New area = 0.9l *0.8 b = 0.72 l*b
hence its a 28% decrease
Hence B
