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if the length of each edge of the rectangular solid above is [#permalink]

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04 Feb 2008, 20:21

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

if the length of each edge of the rectangular solid above is an integer, then the sum of the lengths of all the solid is necessarily divisible by which of the following ?

I'm not sure why you're summing different numbers. The question states that this is a rectangular solid, and the dimensions do not have to follow typical 3-4-5, or 5-12-13 dimensions. We also don't know that the answer will be 3 or 4 because this does not say the rectangular solid is a cube. If it were a cube, then yes, the answer would certainly be 3 or 4, but without knowing that this is a cube, we can't know this for sure.

All information is Insufficent to answer this question.

rino wrote:

A

3,4,5 --> 3+4+5=12 --> 3 or 4

5,12,13 --> 5+12+13=30--> 3 only

thus, A

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

I'm not sure why you're summing different numbers. The question states that this is a rectangular solid, and the dimensions do not have to follow typical 3-4-5, or 5-12-13 dimensions. We also don't know that the answer will be 3 or 4 because this does not say the rectangular solid is a cube. If it were a cube, then yes, the answer would certainly be 3 or 4, but without knowing that this is a cube, we can't know this for sure.

All information is Insufficent to answer this question.

rino wrote:

A

3,4,5 --> 3+4+5=12 --> 3 or 4

5,12,13 --> 5+12+13=30--> 3 only

thus, A

i guess q is asking for a cuboid hence the sum of all side will be

That's a great point. I agree with your answer. It seems that it MIGHT ALSO be divisible by 3 if the cuboid turns out to be an actual cube with 6 equal sides (12 equal edges), but we know it MUST be divisble by 4 for the reason you mentioned.

Kudos.

hibloom wrote:

jallenmorris wrote:

I'm not sure why you're summing different numbers. The question states that this is a rectangular solid, and the dimensions do not have to follow typical 3-4-5, or 5-12-13 dimensions. We also don't know that the answer will be 3 or 4 because this does not say the rectangular solid is a cube. If it were a cube, then yes, the answer would certainly be 3 or 4, but without knowing that this is a cube, we can't know this for sure.

All information is Insufficent to answer this question.

rino wrote:

A

3,4,5 --> 3+4+5=12 --> 3 or 4

5,12,13 --> 5+12+13=30--> 3 only

thus, A

i guess q is asking for a cuboid hence the sum of all side will be

4(L+B+H)==> divissible by 4

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

if the length of each edge of the rectangular solid above is an integer, then the sum of the lengths of all the solid is necessarily divisible by which of the following ?

1. 3 2. 4 3. 5 4. 7 5. 11

intresting question:

length = l bredth = b height = h

since the solid is a ractangular, sum = 4 h + 4 L + 4B = 4 (l + b + h) so the sum should be divisible by 4 no matter the value of l, b, and h.
_________________

I'm not sure why you're summing different numbers. The question states that this is a rectangular solid, and the dimensions do not have to follow typical 3-4-5, or 5-12-13 dimensions. We also don't know that the answer will be 3 or 4 because this does not say the rectangular solid is a cube. If it were a cube, then yes, the answer would certainly be 3 or 4, but without knowing that this is a cube, we can't know this for sure.

All information is Insufficent to answer this question.

rino wrote:

A

3,4,5 --> 3+4+5=12 --> 3 or 4

5,12,13 --> 5+12+13=30--> 3 only

thus, A

u're right, i red it wrong- i thought it was a triangular solid....