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# If the number 481*673 is completely divisible by 9, then the smallest

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If the number 481*673 is completely divisible by 9, then the smallest  [#permalink]

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Updated on: 23 Apr 2019, 06:53
1
00:00

Difficulty:

15% (low)

Question Stats:

86% (01:04) correct 14% (00:48) wrong based on 21 sessions

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If the number 481*673, in which " * " denotes a digit from 0 to 9, is completely divisible by 9, then the smallest whole number in place of * will be

a. 2

b. 5

c. 6

d. 7

e. 9

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Originally posted by AkshdeepS on 23 Apr 2019, 02:21.
Last edited by AkshdeepS on 23 Apr 2019, 06:53, edited 1 time in total.
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Re: If the number 481*673 is completely divisible by 9, then the smallest  [#permalink]

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23 Apr 2019, 02:45
Except for *, the other digits add up to form 29. Of the 5 answer choices, only 9 add up to produce 36, i.e. a number divisible by 9. Therefore, the correct answer is choice D. 7

Concept tested: Divisibility Rules.

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Re: If the number 481*673 is completely divisible by 9, then the smallest  [#permalink]

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23 Apr 2019, 06:14
The notation is confusing, because an asterisk often represents multiplication. If a real GMAT question is using a symbol to represent a digit within a number, the wording of the question always makes that perfectly clear to the test taker. It's also strange that the question asks for the "smallest" value of the star when only one value is possible. Where is the question from?

If we are meant to assume that the star represents a digit, then using the fact that in a multiple of 9, the digits must sum to a multiple of 9, we can determine that the star must be a '7'.
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Re: If the number 481*673 is completely divisible by 9, then the smallest   [#permalink] 23 Apr 2019, 06:14
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