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eunell89
if the operation # is defined by the equation x#y= x-y/2x-y, where 2x ≠ y . the value of which of the following is 0?

(A) -2#2
(B) 2#-2
(C) 2#2
(D) 2#1
(E) 3#2

Explanation:
Given: x#y= x-y/2x-y
Checking By options: c. 2-2/2(2)-2 = 0 As numerator is 0
IMO-C
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