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If the perimeter of a rectangular house is 44 yards, and the length is

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If the perimeter of a rectangular house is 44 yards, and the length is  [#permalink]

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New post 09 Aug 2019, 00:59
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A
B
C
D
E

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Question Stats:

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Re: If the perimeter of a rectangular house is 44 yards, and the length is  [#permalink]

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New post 09 Aug 2019, 01:07
the perimeter of a rectangular house = 44 yards

length of rectangular house = 36 feet = 12 yard (given 1yard = 3 feet)

let the width be w
then the perimeter of rectangular yard = 2(l+w)
44 = 2(12+w)
22 = 12+w
w = 10

width = 10 yard
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Re: If the perimeter of a rectangular house is 44 yards, and the length is  [#permalink]

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New post 09 Aug 2019, 01:46
Bunuel wrote:
If the perimeter of a rectangular house is 44 yards, and the length is 36 feet, what is the width of the house? (1 yard = 3 feet)

A. 10 yards
B. 18 yards
C. 28 feet
D. 32 feet
E. 36 yards


Here in yards Length = L = 36/3 = 12 , Breadth = B
Now 2(L + B) = 44
=> 2B = 44 - 2L
=> B = (44-2*12)/2
=> B = 10

Answer(A)
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If the perimeter of a rectangular house is 44 yards, and the length is  [#permalink]

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New post 10 Aug 2019, 07:39
1
Required - Width = ?
Given - 2(l+w) = 44*3
36+b = 22*3
b = 22*3 - 36
b = 30
Now converting it to yards - 30/3 = 10 yards
So A is the answer.
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Re: If the perimeter of a rectangular house is 44 yards, and the length is  [#permalink]

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New post 12 Aug 2019, 17:50
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Bunuel wrote:
If the perimeter of a rectangular house is 44 yards, and the length is 36 feet, what is the width of the house? (1 yard = 3 feet)

A. 10 yards
B. 18 yards
C. 28 feet
D. 32 feet
E. 36 yards


We know that the length is 36/3 = 12 yards, so we can use the perimeter formula P = 2L + 2W to create the equation:

2 x 12 + 2W = 44

2W = 20

W = 10 yards

Answer: A
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Re: If the perimeter of a rectangular house is 44 yards, and the length is   [#permalink] 12 Aug 2019, 17:50

If the perimeter of a rectangular house is 44 yards, and the length is

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