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If the perimeter of rectangle Q - Confused about simple Q

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Joined: 20 Oct 2011
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Concentration: Sustainability, General Management
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If the perimeter of rectangle Q - Confused about simple Q  [#permalink]

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19 Nov 2011, 13:28
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25% (medium)

Question Stats:

87% (00:45) correct 13% (01:20) wrong based on 52 sessions

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If p is the perimeter of rectangle Q, what is the value of p ?

(1) Each diagonal of rectangle Q has length 10.
(2) The area of rectangle Q is 48.

Now, the obvious choice is [spoiler=]C
, but I figured that is the trap answer and I guessed . Isn't it true that the hypotenuse of a right angled triangle, if 10, will have sides 6-8? Or is this not always the case? I know that if the triangle is not Right angled, then it is not the case;

but here: if the diagonal is 10, and since it is a rectangle, the 2 sides should be 6-8 and thus we can find the perimeter. Of course this is the same answer that you get by substituting values and using 2).

But OA says that we cannot know the sides from 1) or 2) and thus we need 1) and 2).

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-p-is-the-perimeter-of-rectangle-q-what-is-the-value-of-p-135832.html

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Re: If the perimeter of rectangle Q - Confused about simple Q  [#permalink]

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19 Nov 2011, 13:38
+1 C

from 1 we only know about the diagonal lenght and e do not get any information of sided so 1 not sufficient,

From two we know area 2*l*b=48 but l and b can have various values i.e for example 8*6 or12*4 so we cannot get exact values of l and B so 2 not sufficient

Now combining 1 and 2 we get area and diagonal i.e hypotenuse so now solving

we now know that diagonal which has lenght=10 and with two sides of the rectangle form a right angled triangle, and so when you consider above l or B values it only satifies for 8 and 6 or 6 and 8 as 6-8-10 form a right angle traingle, and now we know l and B values so you can find perimeter which is 2(l+B)

Hope this clarifies
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Re: If the perimeter of rectangle Q - Confused about simple Q  [#permalink]

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19 Nov 2011, 13:57
kotela wrote:
+1 C

from 1 we only know about the diagonal lenght and e do not get any information of sided so 1 not sufficient,

From two we know area 2*l*b=48 but l and b can have various values i.e for example 8*6 or12*4 so we cannot get exact values of l and B so 2 not sufficient

Now combining 1 and 2 we get area and diagonal i.e hypotenuse so now solving

we now know that diagonal which has lenght=10 and with two sides of the rectangle form a right angled triangle, and so when you consider above l or B values it only satifies for 8 and 6 or 6 and 8 as 6-8-10 form a right angle traingle, and now we know l and B values so you can find perimeter which is 2(l+B)

Hope this clarifies

Thanks. I understand how to solve it.

My question was simply that, if a right angled triangle is given with a hypotenuse 5 or 10 for instance; can we not automatically assume that it is a 3-4-5 or a 6-8-10 triangle? I suppose you can make fractional values to satisfy this.

Nevermind, I just realized my mistake. I was doing another difficult question earlier where I came across a situation like this, but it was on a coordinate plane, and each value "HAD" to be an integer. Hence with a hypotenuse of 10, the only values for the 2 sides could have been 6 and 8. But I suppose if the integer condition is not specified, then the 2 sides of the right triangle can take any values.

Ok, yea the answer is fine as given. Doh!
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Re: If the perimeter of rectangle Q - Confused about simple Q  [#permalink]

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20 Nov 2011, 01:51
alinomoto wrote:
This is from the OG12, but I am confused about something:

48. If p is the perimeter of rectangle Q, what is the value of p ?

(1) Each diagonal of rectangle Q has length 10.
(2) The area of rectangle Q is 48.

Now, the obvious choice is , but I figured that is the trap answer and I guessed . Isn't it true that the hypotenuse of a right angled triangle, if 10, will have sides 6-8? Or is this not always the case? I know that if the triangle is not Right angled, then it is not the case;

but here: if the diagonal is 10, and since it is a rectangle, the 2 sides should be 6-8 and thus we can find the perimeter. Of course this is the same answer that you get by substituting values and using 2).

But OA says that we cannot know the sides from 1) or 2) and thus we need 1) and 2).

Given:
$$2*(l+b)=p$$
S1: $$l^2+b^2=10^2$$ (Pythagoras theorem) With this, we can't even solve l and b, so no chance of getting the p.

S2:$$l*b=48$$. With this, we can't even solve l and b, so no chance of getting the p.

What we need to solve is p, which is

$$p=2*(l+b)$$
Note that $$(l+b)^2=l^2+b^2+2*l*b$$

Using S1 and S2:
$$(l+b)^2=10^2+2*48$$,
Thus $$(l+b)$$ can be found.

Which means $$p$$ can be found.

Therefore the answer should be "C"
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Re: If the perimeter of rectangle Q - Confused about simple Q  [#permalink]

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23 Nov 2017, 07:53
If p is the perimeter of rectangle Q, what is the value of p?

Question: $$P=2(a+b)=?$$

(1) Each diagonal of rectangle Q has length 10. $$d^2=a^2+b^2=100$$. Not sufficient.
(2) The area of rectangle Q is 48. $$ab=48$$. Not sufficient.

(1)+(2) Square P --> $$P^2=4(a^2+b^2+2ab)$$. Now as from (1) $$a^2+b^2=100$$ and from (2) $$ab=48$$, then $$P^2=4(a^2+b^2+2ab)=4(100+2*48)=4*196$$ --> $$P=\sqrt{4*196}=2*14=28$$. Sufficient.

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http://gmatclub.com/forum/what-is-the-p ... 96381.html

Hope it helps.

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-p-is-the-perimeter-of-rectangle-q-what-is-the-value-of-p-135832.html

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: If the perimeter of rectangle Q - Confused about simple Q &nbs [#permalink] 23 Nov 2017, 07:53
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