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If the population of Townville went from 2105 to 1705, then the percen

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If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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New post 21 Aug 2018, 05:11
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A
B
C
D
E

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  15% (low)

Question Stats:

88% (00:52) correct 13% (00:53) wrong based on 24 sessions

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Re: If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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New post 21 Aug 2018, 05:23
Percentage change = (New value - Old value)/Old value * 100.
New value = 1705
Old value = 2105
Change = (1705-2105)/2015 *100
= (400/2015)*100
= Almost equal to 1/5 or 0.2 ( since denominator is slightly greater than 2000, we can approximate the decrease to 19)
= 19 percent decrease.

A is the answer

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Re: If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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New post 21 Aug 2018, 05:52
Bunuel wrote:
If the population of Townville went from 2105 to 1705, then the percent decrease in population is closest to

A. 19
B. 21
C. 22
D. 23
E. 24



\(\frac{(2105-1705)*100}{2105}\)
=~19
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If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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New post 21 Aug 2018, 06:11
Bunuel wrote:
If the population of Townville went from 2105 to 1705, then the percent decrease in population is closest to

A. 19
B. 21
C. 22
D. 23
E. 24


\(\frac{2105 - 1705}{2015}*100\)

~ \(\frac{2100 - 1700}{2100}*100\)

=\(\frac{400}{2100}*100\)

= \(\frac{4}{21}*100\)

Now, \(\frac{4}{20} = \frac{1}{5}\) = \(20\)%

Since , \(\frac{4}{21} < \frac{4}{20} = x < 20\) %

Among the given options only (A) matches, thus Answer must be (A) 19
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If the population of Townville went from 2105 to 1705, then the percen &nbs [#permalink] 21 Aug 2018, 06:11
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