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If the population of Townville went from 2105 to 1705, then the percen

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Joined: 02 Sep 2009
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If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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21 Aug 2018, 06:11
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15% (low)

Question Stats:

88% (01:10) correct 13% (00:36) wrong based on 29 sessions

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If the population of Townville went from 2105 to 1705, then the percent decrease in population is closest to

A. 19
B. 21
C. 22
D. 23
E. 24

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Re: If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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21 Aug 2018, 06:23
Percentage change = (New value - Old value)/Old value * 100.
New value = 1705
Old value = 2105
Change = (1705-2105)/2015 *100
= (400/2015)*100
= Almost equal to 1/5 or 0.2 ( since denominator is slightly greater than 2000, we can approximate the decrease to 19)
= 19 percent decrease.

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Re: If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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21 Aug 2018, 06:52
Bunuel wrote:
If the population of Townville went from 2105 to 1705, then the percent decrease in population is closest to

A. 19
B. 21
C. 22
D. 23
E. 24

$$\frac{(2105-1705)*100}{2105}$$
=~19
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If the population of Townville went from 2105 to 1705, then the percen  [#permalink]

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21 Aug 2018, 07:11
Bunuel wrote:
If the population of Townville went from 2105 to 1705, then the percent decrease in population is closest to

A. 19
B. 21
C. 22
D. 23
E. 24

$$\frac{2105 - 1705}{2015}*100$$

~ $$\frac{2100 - 1700}{2100}*100$$

=$$\frac{400}{2100}*100$$

= $$\frac{4}{21}*100$$

Now, $$\frac{4}{20} = \frac{1}{5}$$ = $$20$$%

Since , $$\frac{4}{21} < \frac{4}{20} = x < 20$$ %

Among the given options only (A) matches, thus Answer must be (A) 19
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If the population of Townville went from 2105 to 1705, then the percen   [#permalink] 21 Aug 2018, 07:11
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