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05 Jun 2019, 00:28
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Difficulty:
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Question Stats:
67% (01:31) correct
33%
(01:42)
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If the ratio of 2a to b is 8 times the ratio of b to a, then \(\frac{b}{a}\) could be which of the following?
I. \(-2\)
II. \(-\frac{1}{2}\)
III. \(\frac{1}{2}\)
A. I only
B. II only
C. III only
D. II and III only
E. I, II and III
I. \(-2\)
II. \(-\frac{1}{2}\)
III. \(\frac{1}{2}\)
A. I only
B. II only
C. III only
D. II and III only
E. I, II and III
Updated on: 05 Jun 2019, 00:37
Originally posted by Archit3110 on 05 Jun 2019, 00:31.
Last edited by Archit3110 on 05 Jun 2019, 00:37, edited 2 times in total.
Last edited by Archit3110 on 05 Jun 2019, 00:37, edited 2 times in total.
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Bunuel
If the ratio of 2a to b is 8 times the ratio of b to a, then \(\frac{b}{a}\) could be which of the following?
I. \(-2\)
II. \(-\frac{1}{2}\)
III. \(\frac{1}{2}\)
A. I only
B. II only
C. III only
D. II and III only
E. I, II and III
I. \(-2\)
II. \(-\frac{1}{2}\)
III. \(\frac{1}{2}\)
A. I only
B. II only
C. III only
D. II and III only
E. I, II and III
given
2a/b=8*b/a
solve
a^2=4*b^2
square
a=2b
b/a= +/-1/2
IMOD
05 Jun 2019, 00:36
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Bunuel
If the ratio of 2a to b is 8 times the ratio of b to a, then \(\frac{b}{a}\) could be which of the following?
I. \(-2\)
II. \(-\frac{1}{2}\)
III. \(\frac{1}{2}\)
A. I only
B. II only
C. III only
D. II and III only
E. I, II and III
I. \(-2\)
II. \(-\frac{1}{2}\)
III. \(\frac{1}{2}\)
A. I only
B. II only
C. III only
D. II and III only
E. I, II and III
IMO D.
solving the equation-
2a/b = 8b/a we get (b/a)^2 = 1/4
So, b/a = +- 1/2
