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If the ratio of Rate of filling of two Pipes A and B is

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If the ratio of Rate of filling of two Pipes A and B is  [#permalink]

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New post Updated on: 23 Oct 2018, 05:16
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Question Stats:

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If the ratio of Rate of filling of two Pipes A and B is
3:2. They can fill 5/6th of a Tank together in 20 minutes. How many minutes will A alone take to fill the Tank?

(A) 25
(B) 32
(C) 40
(D) 48
(E) 60

Posted from my mobile device

Originally posted by jackfr2 on 23 Oct 2018, 04:53.
Last edited by chetan2u on 23 Oct 2018, 05:16, edited 1 time in total.
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Re: If the ratio of Rate of filling of two Pipes A and B is  [#permalink]

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New post 23 Oct 2018, 05:20
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jackfr2 wrote:
If the ratio of Rate of filling of two Pipes A and B is
3:2. They can fill 5/6th of a Tank together in 20 minutes. How many minutes will A alone take to fill the Tank?

(A) 25
(B) 32
(C) 40
(D) 48
(E) 60

Posted from my mobile device


Since the ratio is 3:2, the amount of work done is \(\frac{3}{(3+2)}:\frac{2}{(3+2)}\)..
So A does 3/5th of 5/6th work in 20 min or \(\frac{3}{5}\)*\(\frac{5}{6}\)*t=20.......t=2*20=40 min...

C
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If the ratio of Rate of filling of two Pipes A and B is  [#permalink]

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New post 23 Oct 2018, 05:37
jackfr2 wrote:
If the ratio of Rate of filling of two Pipes A and B is 3:2. They can fill 5/6th of a Tank together in 20 minutes. How many minutes will A alone take to fill the Tank?

(A) 25
(B) 32
(C) 40
(D) 48
(E) 60

Posted from my mobile device



ALTERNATE METHOD WITHOUT USE OF ANY VARIBALE

\(\frac{5}{6}^{th}\) of the work is done in \(20\) minutes.

Complete work is done in \(20*\frac{6}{5} = 24\) Minutes

Further both A and B working at the job completes the task in 24 minutes...

So, Let the total work be \(24*(3+2) = 120\) Units

Working alone A , completes the job in 120/3 = 40 Minutes, Answer must be (C)
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If the ratio of Rate of filling of two Pipes A and B is  [#permalink]

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New post 23 Oct 2018, 11:53
jackfr2 wrote:
If the ratio of Rate of filling of two Pipes A and B is
3:2. They can fill 5/6th of a Tank together in 20 minutes. How many minutes will A alone take to fill the Tank?

(A) 25
(B) 32
(C) 40
(D) 48
(E) 60

Posted from my mobile device


Given: For every 3 units that Pipe A fills in a minute, Pipe B would fill 2 units.

Together in 20 minutes, they fill 20*(3+2) = 100 units capacity, which is \(\frac{5}{6}\)th of the tank.
Using this information, we can calculate the total capacity of the tank which is \(\frac{6}{5}*100 = 120\) units.

Therefore, Pipe A will need \(\frac{120}{3} = 40\) minutes(Option C) in order to fill the tank
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Re: If the ratio of Rate of filling of two Pipes A and B is  [#permalink]

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New post 29 Oct 2018, 10:18
jackfr2 wrote:
If the ratio of Rate of filling of two Pipes A and B is
3:2. They can fill 5/6th of a Tank together in 20 minutes. How many minutes will A alone take to fill the Tank?

(A) 25
(B) 32
(C) 40
(D) 48
(E) 60

Posted from my mobile device


OA:C

Let Rate of filling the tank by Pipe A: \(3x\) Tank/Minute
Let Rate of filling the tank by Pipe B: \(2x\) Tank/Minute

\(20( 3x+2x)=\frac{5}{6}\)

\(100x=\frac{5}{6}\)

\(x=\frac{5}{100*6}=\frac{1}{20*6}=\frac{1}{120}\)

Rate of filling the tank by Pipe A: \(3*\frac{1}{120}\) Tank/Minute \(=\frac{1}{40}\)Tank/Minute

Time taken by A to fill \(1\) tank \(= \frac{1 Tank}{\frac{1}{40}Tank/Minute}=40\) Minutes
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Re: If the ratio of Rate of filling of two Pipes A and B is &nbs [#permalink] 29 Oct 2018, 10:18
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