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04 Jul 2022, 05:45
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (00:42) correct
9%
(01:47)
wrong
based on 44
sessions
History
Date
Time
Result
Not Attempted Yet
If the sum and difference of two numbers are 20 and 8 respectively, then the difference of their squares is:
(A) 12
(B) 28
(C) 80
(D) 160
(E) 180
(A) 12
(B) 28
(C) 80
(D) 160
(E) 180
04 Jul 2022, 06:12
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Given a+b=20 and a-b=8
Since \(a^2-b^2\)=\((a-b) (a+b)\)
\(a^2-b^2\)= 20x8
\(a^2-b^2\)=160
Hence, D
Since \(a^2-b^2\)=\((a-b) (a+b)\)
\(a^2-b^2\)= 20x8
\(a^2-b^2\)=160
Hence, D
04 Jul 2022, 09:00
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This question is simple but in the real test can be a bit scary due to the calculations.
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