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Let the temperature of the 4th day be: x

\(\frac{+9-6+8+x}{4}\) =4

11+x=16
x= 16-11= +5

Answer: E.

Kudos please if you like my explanation!
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Let the temperature of the 4th day be: x

+9−6+8+x4+9−6+8+x4 =4

11+x=16
x= 16-11= +5

Answer: E.
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Bunuel
If the temperature readings at noon for three consecutive days are +9°,—6°, and +8°, what must the reading be at noon on the fourth day for the average (arithmetic mean) noon temperature of all four days to be +4°?

A. –11°
B. –7°
C. +2°
D. +4°
E. +5°


best way => you want 4 as average=> compare wrt 4 up or down
9 = u went 5 up
-6 = u went 10 down => 5 down nett
+8 = u went 4 up => 1 down nett
assume 4th one be 4 so if u take 4 => u are still 1 down in nett
to raise by 1 you should have 5 in th place so that when 5 is there 1 up will nullify 1 down

=> 4 is avg when => 5 is the answer

==========================

9 is 5 higher
-6 is 10 lower ( net 5 lower)
8 is 4 higher ( net 1 lower)
5 is 1 higer ( net same )

5 is answer
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Bunuel
If the temperature readings at noon for three consecutive days are +9°,—6°, and +8°, what must the reading be at noon on the fourth day for the average (arithmetic mean) noon temperature of all four days to be +4°?

A. –11°
B. –7°
C. +2°
D. +4°
E. +5°

We can let n = the temperature on the fourth day and use the formula sum/number = average to create the equation:

(9 + (-6) + 8 + n)/4 = 4

11 + n = 16

n = 5

Answer: E
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Hello from the GMAT Club BumpBot!

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