bmwhype2 wrote:
Three circles have radii 1, 2, and 3 respectively lie on the plane. Do any two circles intersect?
1. Centers of the circles form an equilateral triangle with height 2*sqrt(3)
2. Centers of the circles do not lie on the same line
Can someone draw out the answer? Regards
Using statement 1, make an equilateral triangle with side \(2\sqrt{3}\) which is a little more than 3.4 since \(\sqrt{3}\) is a little more than 1.7.
On any one vertex, we will have the circle with the radius 1. On another, you will have to draw a circle with radius 3 but since the
length of the side is only 3.4, this circle will intersect the circle with radius 1. Hence, statement 1 alone is sufficient.
Statement 2 doesn't tell us where the circles lie. They could lie very close to each other and intersect or very far from each other and not intersect. This statement alone is not sufficient.
Answer (A)
As per you "length of the side is only 3.4" but according to me the lenght of side should be 4.
So, side= 4..
Thanks and Regards,
Prakhar