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Clearly tuvw are factors of 108. To find the greatest possible value of t-w we need to maximise t and minimise w

Lets look at the factors of 108
1-108
2-54
3-36
4-27
6-18
9-12

We need 4 factors and W is our minimum
Choose w=1
1-108
2-54
3-36
4-27
6-18
9-12

In the right hand column choose a value for t, you can test numbers but you'll see that 18 is the only one that works as
So 18-1 = 17
1-108
2-54
3-36
4-27
6-18
9-12
We can process eliminate the answers by asking whether we can obtain a given value.
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adkikani
If tuvw = 108, and t, u, v, and w are all positive integers such that t > u > v > w, what is the greatest possible value for t - w?

A. 1
B. 16
C. 17
D. 18
E. 19

The prime factorization of \(108 = 2^2 * 3^3\).

We're told \(w < v < u < t\). Using the factors, we need to create 4 different integers.

We can get the numbers \(1 < 2 < 3 < 18\)

\(18 - 1 = 17\).

Answer is C.
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To MAXIMIZE the difference ,we need to minimize w.
w is a factor of 108 and the minimum such a factor is 1.Hence w=1.
108=3*3*3*2*2*1
So w=1 (smallest)
Next smallest v=2
and u=3 in the same way.
So, w, v, u are minimized and t is maximized if w=1,v=2,u=3.
This means t=18
[ t=(108/3*2)=108/6=18 ]
So t-w =18-1=17 (C)

ALTERNATELY ,you can also use options in the following way:
Eliminate (a) because t-w cannot be 1 (As t>u>v>w and belong to integers)
Now add 1 to the options and see which of them is a factor of 108.
Eliminate (b),(d) and (e)
Only (c) which is 17 when added to 1 gives 18 that is a factor of 108.
Hence (c)
Hope this helps! Keep studying!:)
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adkikani
If tuvw = 108, and t, u, v, and w are all positive integers such that t > u > v > w, what is the greatest possible value for t - w?

A. 1
B. 16
C. 17
D. 18
E. 19
\(­108 = 1*2^2*3^3\)

So, \(t = 18\) , \(u = 3\) , \(v = 2\) & \(w = 1\)

Hence, \(t - w = 18 - 1 => 17\), Answer will be (C)
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