144144 wrote:
Guys, whats the most efficient way to conclude that:
u^3 < v and u < v^3 (By cubing both sides)
This is only possible only when u < v
thanks.
A > B > 0 and P > Q > 0. Then, as with addition, we can multiply inequalities with the same direction: A*P > B*Q must be true. And, as with subtraction, we can divide inequalities with the opposite direction: A/Q > B/P. Again, remember the caveat: everything must be positive for these patterns to work. If anything can be negative, things get much more complicated, so complicated that the GMAT won’t ask about them. >>>from
Magooshin this case, you can conclude u^4<v^4Square Root Property
Taking a square root will not change the inequality (but only when both a and b are greater than or equal to zero).
If a ≤ b then √a ≤ √b
(for a,b ≥ 0)
in this case,you can say u<v.