Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

It is currently 16 Jul 2019, 12:11

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

If u and v are positive real numbers, is u>v? 1. u^3/v

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Manager
Manager
avatar
Status: Only GMAT!!
Joined: 17 Sep 2010
Posts: 64
WE 1: 5.5+ years IT Prof.
If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 16 Jul 2011, 07:17
2
6
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

40% (02:25) correct 60% (02:12) wrong based on 234 sessions

HideShow timer Statistics


If u and v are positive real numbers, is u>v?

1. u^3/v < 1

2. (u^(1/3))/v < 1
Most Helpful Community Reply
Retired Moderator
avatar
B
Joined: 16 Nov 2010
Posts: 1360
Location: United States (IN)
Concentration: Strategy, Technology
Reviews Badge
Re: If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 16 Jul 2011, 08:01
4
4
(1)

u^3/v < 1

=> u^3 < v (Because v is positive, we can multiply both sides by v)

If u = 2 and v = 9, then the condition holds and u < v

If u = 1/2 and v = 1/3, then the condition holds and u > v

Insufficient

(2)

(u)^1/3 < v

If u = 8 and v = 3 then the condition holds and u > v

If u = 8 and v = 9, then the condition holds and u < v

Insufficient

(1) + (2)

u^3 < v and u < v^3 (By cubing both sides)

This is only possible only when u < v

Sufficient

Answer - C
_________________
Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

GMAT Club Premium Membership - big benefits and savings
General Discussion
Manager
Manager
avatar
Joined: 28 May 2011
Posts: 149
Location: United States
Concentration: General Management, International Business
GMAT 1: 720 Q49 V38
GPA: 3.6
WE: Project Management (Computer Software)
Re: If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 16 Jul 2011, 07:50
vivgmat wrote:
If u and v are positive real numbers, is u>v?

1. u^3/v < 1

2. (u^1/3) /v < 1



First Statement can be written as

u^3 < v, sufficient; A cube of one number (u) can be lesser than another number (v) only if u<v

Second statement can be written as

u^1/3 < v, insufficient; can be tested with ( u=9, v=5), (u=9, v=10)

I would go with A
_________________
-------------------------------------------------------------------------------------------------------------------------------
http://gmatclub.com/forum/a-guide-to-the-official-guide-13-for-gmat-review-134210.html
-------------------------------------------------------------------------------------------------------------------------------
Manager
Manager
avatar
Joined: 28 May 2011
Posts: 149
Location: United States
Concentration: General Management, International Business
GMAT 1: 720 Q49 V38
GPA: 3.6
WE: Project Management (Computer Software)
Re: If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 16 Jul 2011, 08:13
Yaa now I get it you are right. In the first statement, I missed the condition of (U<1, V<1)

+1 subhashghosh
_________________
-------------------------------------------------------------------------------------------------------------------------------
http://gmatclub.com/forum/a-guide-to-the-official-guide-13-for-gmat-review-134210.html
-------------------------------------------------------------------------------------------------------------------------------
Senior Manager
Senior Manager
User avatar
Joined: 08 Nov 2010
Posts: 313
WE 1: Business Development
GMAT ToolKit User
Re: If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 31 Jul 2011, 10:46
Guys, whats the most efficient way to conclude that:
u^3 < v and u < v^3 (By cubing both sides)

This is only possible only when u < v

thanks.
_________________
Intern
Intern
avatar
B
Joined: 25 Mar 2016
Posts: 39
Location: India
Concentration: Finance, General Management
WE: Other (Other)
Re: If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 24 Apr 2016, 19:45
what about if v is negative
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56244
Re: If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 24 Apr 2016, 22:41
1
Intern
Intern
avatar
B
Joined: 16 Aug 2018
Posts: 28
Concentration: General Management, Strategy
Schools: Guanghua"21 (A)
GMAT 1: 700 Q49 V36
Re: If u and v are positive real numbers, is u>v? 1. u^3/v  [#permalink]

Show Tags

New post 26 Aug 2018, 02:08
144144 wrote:
Guys, whats the most efficient way to conclude that:
u^3 < v and u < v^3 (By cubing both sides)

This is only possible only when u < v

thanks.


A > B > 0 and P > Q > 0. Then, as with addition, we can multiply inequalities with the same direction: A*P > B*Q must be true. And, as with subtraction, we can divide inequalities with the opposite direction: A/Q > B/P. Again, remember the caveat: everything must be positive for these patterns to work. If anything can be negative, things get much more complicated, so complicated that the GMAT won’t ask about them. >>>from Magoosh
in this case, you can conclude u^4<v^4

Square Root Property

Taking a square root will not change the inequality (but only when both a and b are greater than or equal to zero).

If a ≤ b then √a ≤ √b
(for a,b ≥ 0)

in this case,you can say u<v.
GMAT Club Bot
Re: If u and v are positive real numbers, is u>v? 1. u^3/v   [#permalink] 26 Aug 2018, 02:08
Display posts from previous: Sort by

If u and v are positive real numbers, is u>v? 1. u^3/v

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne